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一些i / o问题(Some i/o problems)

 免责声明：这是一项任务。 如果你觉得我只是“请你为我做功课”让我知道，我会问一个更广泛的问题，或者只是给你一些提示，如果你能取悦。  
 好的，我有两套100个文件。 第一组称为cell_spks_n，其中n = 1，...，100，第二组称为cell_dirs_n，其中n = 1，...，100。 numpy的loadtxt将这些文件加载到5x8数组中，这是完美的。 我想加载这些并为它们做一些事情。 现在我的问题是命名所有这些文件 。 我想到制作两个名为dirs和spks的列表，并按顺序将数组存储在其中。 然而出了问题，它只附加了一个 numpy加载的元素，我不知道出了什么问题。  
from numpy import *

files = 100
for i in range(1, files+1):
    dirs = []
    spks = []
    if (0<i<9):
        dirs_name = 'neurondata/cell_dirs_00' + str(i) + '.txt' 
        spks_name = 'neurondata/cell_spks_00' + str(i) + '.txt'
        dirs.append(loadtxt(dirs_name))
        spks.append(loadtxt(spks_name))
    elif (9<i<=99):
        dirs_name = 'neurondata/cell_dirs_0' + str(i) + '.txt' 
        spks_name = 'neurondata/cell_spks_0' + str(i) + '.txt'
        dirs.append(loadtxt(dirs_name))
        spks.append(loadtxt(spks_name))
    else:
        dirs.append(loadtxt('neurondata/cell_dirs_100.txt'))
        spks.append(loadtxt('neurondata/cell_spks_100.txt'))


# Fancy stuff gets done here
 
 我认为将这些作为数组加载甚至可能是一个坏主意，我将不得不考虑我的索引来访问数据。 理想的情况是有某种循环，如下所示：  
for i in range(1,files+1):
    spk_i = loadtxt('cell_spks_i')
    dir_i = loadtxt('cell_dirs_i')
 
 思考？  
 编辑：我忘记了一些输出  
 如果我说  
for item in spks:
    print item
print shape(spks)
 
 我得到了输出  
[[ 25.287356   23.655914   22.988506   14.285714    2.3809524   4.3478261
19.354839   11.764706 ]
[ 16.129032   26.666667   19.565217    7.2289157   5.8823529  13.861386
7.0588235  12.195122 ]
[ 13.157895   16.86747    26.190476   29.62963    12.121212   12.307692
27.5        19.047619 ]
[ 18.518519   25.396825   34.482759   14.814815   20.224719    9.4117647
6.6666667  21.686747 ]
[ 32.55814    22.988506   26.506024   21.782178   13.114754    2.7777778
14.814815    8.6021505]]
(1, 5, 8)

Disclaimer: This is for an assignment. If you feel I'm just "asking you to do my homework for me" let me know and I'll ask a more broad question, or just give me hints if you can please. 
Ok so I've got two sets of 100 files. The first set is called cell_spks_n where n=1,...,100 and the second set is called cell_dirs_n, where n=1,...,100. numpy's loadtxt loads these files in a 5x8 array which is perfect. I want to load these all up and do some stuff to them. Now my issue is naming all these files. I thought of making two lists called dirs and spks, and storing the arrays in them sequentially. However something goes wrong and it only appends one element that numpy loads and I'm not sure what's going wrong. 
from numpy import *

files = 100
for i in range(1, files+1):
    dirs = []
    spks = []
    if (0<i<9):
        dirs_name = 'neurondata/cell_dirs_00' + str(i) + '.txt' 
        spks_name = 'neurondata/cell_spks_00' + str(i) + '.txt'
        dirs.append(loadtxt(dirs_name))
        spks.append(loadtxt(spks_name))
    elif (9<i<=99):
        dirs_name = 'neurondata/cell_dirs_0' + str(i) + '.txt' 
        spks_name = 'neurondata/cell_spks_0' + str(i) + '.txt'
        dirs.append(loadtxt(dirs_name))
        spks.append(loadtxt(spks_name))
    else:
        dirs.append(loadtxt('neurondata/cell_dirs_100.txt'))
        spks.append(loadtxt('neurondata/cell_spks_100.txt'))


# Fancy stuff gets done here
 
I think it might even be a bad idea loading these as arrays which I'll have to mind my indexing to access the data. The ideal case would be to have some kind of loop that goes something like this: 
for i in range(1,files+1):
    spk_i = loadtxt('cell_spks_i')
    dir_i = loadtxt('cell_dirs_i')
 
Thoughts? 
Edit: I forgot to some output  
If I say  
for item in spks:
    print item
print shape(spks)
 
I get as output  
[[ 25.287356   23.655914   22.988506   14.285714    2.3809524   4.3478261
19.354839   11.764706 ]
[ 16.129032   26.666667   19.565217    7.2289157   5.8823529  13.861386
7.0588235  12.195122 ]
[ 13.157895   16.86747    26.190476   29.62963    12.121212   12.307692
27.5        19.047619 ]
[ 18.518519   25.396825   34.482759   14.814815   20.224719    9.4117647
6.6666667  21.686747 ]
[ 32.55814    22.988506   26.506024   21.782178   13.114754    2.7777778
14.814815    8.6021505]]
(1, 5, 8)

原文：https://stackoverflow.com/questions/20052527

更新时间：2023-03-04 20:03

最满意答案

 最简单的方法。  
import { Http } from '@angular/http';


export class CustomComponent implements OnInit {

length: number;

constructor(private http: Http){

this.http.request('www.url...',{method:'GET'}).map(response => response.json()).subscribe(result=>{
this.length=result.length;
});

}

}

Easiest method. 
import { Http } from '@angular/http';


export class CustomComponent implements OnInit {

length: number;

constructor(private http: Http){

this.http.request('www.url...',{method:'GET'}).map(response => response.json()).subscribe(result=>{
this.length=result.length;
});

}

}

一些i / o问题(Some i/o problems)

最满意答案

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