首页 \ 问答 \ 如何在Go中使用带有NewServeMux的websocket?(How to use websocket with NewServeMux in Go?)

如何在Go中使用带有NewServeMux的websocket?(How to use websocket with NewServeMux in Go?)

我收到一条错误消息:无法在mx.HandleFunc的参数中使用websocket.Handler(handler)(类型websocket.Handler)作为类型func(http.ResponseWriter,* http.Request)

在以下代码中

package main

import (
    "golang.org/x/net/websocket"
    "net/http"
)

func handler(ws *websocket.Conn) {
    // TODO
}
func main() {
    mx := http.NewServeMux()
    mx.HandleFunc("/ws", websocket.Handler(handler)) // error

    http.ListenAndServe("localhost:8888", mx)
}

I got an error message: cannot use websocket.Handler(handler) (type websocket.Handler) as type func(http.ResponseWriter, *http.Request) in argument to mx.HandleFunc

in following code

package main

import (
    "golang.org/x/net/websocket"
    "net/http"
)

func handler(ws *websocket.Conn) {
    // TODO
}
func main() {
    mx := http.NewServeMux()
    mx.HandleFunc("/ws", websocket.Handler(handler)) // error

    http.ListenAndServe("localhost:8888", mx)
}

原文:https://stackoverflow.com/questions/46520738
更新时间:2023-10-07 08:10

最满意答案

似乎你在错误的项目上使用扩展操作符。 你应该使用它来代替:

        var newstate = Object.assign({}, state,
            {items: [...state.items, action.payload.found]}
        );

你的代码{items: [state.items, ...action.payload.found]}实际上试图传播作为对象的action.payload.found ,然后返回一个数组,其中第一项是旧数组,后面跟着数值从action.payload.found

例如,假设原始的state.items[A, B, C]action.payload.found{id: "100", price: 10} ,然后{items: [state.items, ...action.payload.found]}实际上会返回[[A, B, C], "100", 10] 。 但是,您希望它返回[A, B, C, {id: "100", price: 10}] 。 因此你需要传播state.items


Seems you are using spread operator on wrong item. You should use this instead:

        var newstate = Object.assign({}, state,
            {items: [...state.items, action.payload.found]}
        );

Your code {items: [state.items, ...action.payload.found]} actually tried to spread action.payload.found which is an object and then returned an array where the first item was the old array followed by the values from action.payload.found

For instance assume original state.items was [A, B, C] and action.payload.found was {id: "100", price: 10}, then {items: [state.items, ...action.payload.found]} would actually return [[A, B, C], "100", 10]. However you want it to return [A, B, C, {id: "100", price: 10}] instead. Therefore you need to spread state.items.

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