首页 \ 问答 \ 如何在不激活所述virtualenv的情况下在virtualenv中找到一个模块?(How to find a module in a virtualenv without activating said virtualenv?)

如何在不激活所述virtualenv的情况下在virtualenv中找到一个模块?(How to find a module in a virtualenv without activating said virtualenv?)

假设我有以下设置:

mkdir test && cd test
virtualenv .venv
source .venv/bin/activate
pip install django
mkdir mod1
touch mod1/__init__.py
echo "a = 1" > mod1/mod2.py

这给了我:

test/.venv
test/mod1/__init__.py
test/mod1/mod2.py

我该如何写这个函数:

def get_module(module_name, root_path, virtualenv_path=None)

为了使这个工作:

project_root_path = "./test"
project_virtualenv_path = "./test/.venv"

get_module("mod1.mod2", project_root_path, project_virtualenv_path)
get_module("django.contrib.auth", project_root_path, project_virtualenv_path)

假设我没有激活./test/.venv

我想这样做的原因是因为我正在开发一个vim插件,它将在import语句的python文件中实现gf功能。 我也试图支持virtualenvs。

编辑:

此外,脚本不应通过添加或附加到sys.path来更改当前运行时。 这应该通过vim python绑定在vim内部运行,我不认为改变vim python运行时是一个好主意。

get_module可以返回一个模块对象,也可以返回模块的路径,这正是我基本上要寻找的。


Suppose I have the following setup:

mkdir test && cd test
virtualenv .venv
source .venv/bin/activate
pip install django
mkdir mod1
touch mod1/__init__.py
echo "a = 1" > mod1/mod2.py

Which gives me:

test/.venv
test/mod1/__init__.py
test/mod1/mod2.py

How would I write this function:

def get_module(module_name, root_path, virtualenv_path=None)

In order for this to work:

project_root_path = "./test"
project_virtualenv_path = "./test/.venv"

get_module("mod1.mod2", project_root_path, project_virtualenv_path)
get_module("django.contrib.auth", project_root_path, project_virtualenv_path)

Assuming I don't have ./test/.venv activated.

The reason I want to do this, is because I'm working on a vim plugin which would implement gf functionality in a python file on an import statement. I'm trying to support virtualenvs as well.

EDIT:

Also, the script should not alter the current runtime, by adding or appending to sys.path. This should run inside vim, via the vim python bindings, and I don't think altering the vim python runtime would be a good idea.

get_module could either return a module object, or the path to the module, which is what I'm basically looking for.


原文:https://stackoverflow.com/questions/11471566
更新时间:2024-01-09 12:01

最满意答案

从'inside'函数调用的mfilename返回函数路径和名称。

fullPath = mfilename('fullpath');
pathString = fileparts(fullPath);
dataPath = [ pathString filesep 'data.csv'];
csvwrite(dataPath, data(:));

mfilename called from 'inside' a function returns the function path and name.

fullPath = mfilename('fullpath');
pathString = fileparts(fullPath);
dataPath = [ pathString filesep 'data.csv'];
csvwrite(dataPath, data(:));

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