==或.Equals（）(== or .Equals())

 你的代码很好，但你忘了检查所有元素，因为在找到第一个元素3的for循环中，它将进入中断状态，因此它不会检查其余的3s元素。 尝试这个代码，当你发现这个元素删除它并转到下一个时，你也不需要中断： 
 
 PS：你需要在每次删除过程后最小化它的计数变量，在你的代码中它将被执行一次。 
 
public void remove(int value) {
    IntegerNode curr = head;
    IntegerNode prev = null;

        for (curr = head; curr != null; curr = curr.next) {
            if(curr.item == value) {
                if (prev == null) {
                    head = curr.next;
                } else {
                    prev.next = curr.next;
                }
                    count--;
            }
            prev = curr;
        }
}

your code is good but you forgot to check all elements because in for loop when the first element 3 is found will get into break , so it won't check the rest of 3s elements . try this code ,also you don't need break just when you find this element delete it and go to the next:
 
PS : The count variable you need to minimize it after every deletion process , in your code it will be executed just for one time .
 
public void remove(int value) {
    IntegerNode curr = head;
    IntegerNode prev = null;

        for (curr = head; curr != null; curr = curr.next) {
            if(curr.item == value) {
                if (prev == null) {
                    head = curr.next;
                } else {
                    prev.next = curr.next;
                }
                    count--;
            }
            prev = curr;
        }
}