在HTML5中拖放画布(Drag and Drop canvas in HTML5)
如何在HTML 5中创建拖放画布? (画布内的东西)以及如何捕获掉落的位置?
How to create a drag and drop canvas in HTML 5 ? (something inside the canvas) and how to capture the dropped location ?
原文:https://stackoverflow.com/questions/4468940
更新时间:2023-05-23 19:05
最满意答案
delete from temp1 where Title IN (SELECT Title FROM temp1 where [flag] = 'No')
delete from temp1 where Title IN (SELECT Title FROM temp1 where [flag] = 'No')
相关问答
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我要做的是在你的桌子上运行一个快速查询: Dim db as Database Dim rec as Recordset Set db = CurrentDB Set rec = db.OpenRecordset ("SELECT * FROM MyTable WHERE MyValue = '" & Me.MyValue & "'") If rec.EOF = true then 'No match found, so the value isn't in the table. Add it. ...
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您不能以这种方式删除记录,主要问题是您无法使用子查询来指定LIMIT子句的值。 这个工作(在MySQL 5.0.67中测试): DELETE FROM `table` WHERE id NOT IN ( SELECT id FROM ( SELECT id FROM `table` ORDER BY id DESC LIMIT 42 -- keep this many records ) foo ); 中间子查询是必需的。 没有它,我们会遇到两个错误: SQL错 ...
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你可以简单地使用range查询和一些日期数学,如下所示: { "query": { "range": { "date_time": { "lt" : "now/d" } } } } You can simply use a range query and some date math like this: { "query": { "range": { "date_time": { "lt" : "no ...
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请从表别名“a。,b”中删除点(。)。 并重试。 Please remove dot(.) from table alias "a., b." and retry.
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第一个解决方案 ,它很灵活,因为您可以添加比COL_A和COL_B更多的列: -- create table with identity filed -- using idenity we can decide which row we can delete create table MY_TABLE_COPY ( id int identity, COL_A varchar(30), COL_B varchar(30) /* other columns */ ) go - ...
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据推测,你想用于: DELETE FROM myTable WHERE columnA IN (SELECT MAX(columnA) as columnA FROM myTable GROUP BY -- the 50 other columns above HAVING count(*) > 1 ); 这假设colum ...
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请看一下这篇文章,我希望这将解决您的问题使用DataAdapter执行批处理操作(ADO.NET) Please have a look at this article and I hope this will resolve your problem Performing Batch Operations Using DataAdapters (ADO.NET)
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查询删除记录(Query to delete records)[2022-11-06]
delete from temp1 where Title IN (SELECT Title FROM temp1 where [flag] = 'No') delete from temp1 where Title IN (SELECT Title FROM temp1 where [flag] = 'No') -
尝试这个 DELETE FROM Project WHERE Project_ID = 14 AND Project_ID IN (SELECT ProjectID FROM Project_Assigned WHERE ProjectID = 14) Try this DELETE FROM Project WHERE Project_ID = 14 AND Project_ID IN (SELECT ProjectID FROM Project_Assigned ...
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尝试这个: UPDATE YourTable t INNER JOIN(SELECT max(s.id) as max_id,s.fname,s.lname,GROUP_CONCAT(distinct(s.skills)) as skill_str FROM YourTable s GROUP BY s.fname,s.lname) t1 ON (t.lname = t1.lname and t.fname = t1.fname AND t.id = t1.ma ...