函数计算平均值(Function calculate the mean)

 我试图用一个函数来计算数字的平均值，我的数组中有一个整数倍数的整数，但我只是觉得我的函数很糟糕，关于如何改进我的函数的任何建议？ 
 
#include <stdio.h>

double meanOfPositive(double *arr, int length);

int main()
{
    int numValue = 6;
    double numbers[] = { 1.1, 2.2, 3.3, 4.4, 5.5, 6.6 };
    double mean2;

    mean2 = meanOfPositive(numValue, numbers);

    printf("Mean of all numbers is %.2f", mean2);
    getchar();
    return 0;
}

double meanOfPositive(double *arr, int length)
{
    int numValue = 6;
    double tot = 0;
    double mean = 0;
    double numbers[] = { 1.1, 2.2, 3.3, 4.4, 5.5, 6.6};

    for (int i = 0; i < numValue; i++)
    {
        tot = tot + numbers[i];
    }
    mean = tot / numValue;
    return mean;
}

I'm trying to calculate the mean of numbers using a function with an int number of the total double numbers in my array, but i just feel my function is awful, any advice on how i can improve my function?
 
#include <stdio.h>

double meanOfPositive(double *arr, int length);

int main()
{
    int numValue = 6;
    double numbers[] = { 1.1, 2.2, 3.3, 4.4, 5.5, 6.6 };
    double mean2;

    mean2 = meanOfPositive(numValue, numbers);

    printf("Mean of all numbers is %.2f", mean2);
    getchar();
    return 0;
}

double meanOfPositive(double *arr, int length)
{
    int numValue = 6;
    double tot = 0;
    double mean = 0;
    double numbers[] = { 1.1, 2.2, 3.3, 4.4, 5.5, 6.6};

    for (int i = 0; i < numValue; i++)
    {
        tot = tot + numbers[i];
    }
    mean = tot / numValue;
    return mean;
}

原文：https://stackoverflow.com/questions/43683311