首页 \ 问答 \ 如何在cakephp中显示最后一个链接(How to show the last link in cakephp)

如何在cakephp中显示最后一个链接(How to show the last link in cakephp)

我在cakephp做一个项目。 在这里我需要一个不同的布局。 请看看我的分页要求

<<First  <Prev  1|2|3|4|5|6  Next>  Last>>

有6个页面项目,每当我到达页面6时,蛋糕将不会显示最后>>,同样的情况在第一个按钮按钮中,它会自动隐藏。

但是我需要为我的分页保留上面的布局,如果我点击任何链接,它应该显示所有链接。

我怎么处理这个? 可能吗?


I am doing a project in cakephp. Here I need a different layout. Please have a look at my pagination requirements

<<First  <Prev  1|2|3|4|5|6  Next>  Last>>

There are 6 page items ,whenever I reached the page 6 , cake won't display the Last>> ,same case in First Button Button ,it hides that automatically.

However I need to keep the above layout for my pagination , If I click any link ,it should display the all links.

How Could I handle this? Is it possible?


原文:https://stackoverflow.com/questions/9798945
更新时间:2022-03-04 14:03

最满意答案

您可以使用:

df = DataFrame(
  cat = ["a", "b", "c","a"],
  prices = [1,2,3,4],
  vol    = [10,20,30,40],
)

df2 = by(df, :cat) do sub
      t = DataFrame(prices=mean(sub[:prices]), vol=sum(sub[:vol]))
end

df2

3×3 DataFrames.DataFrame
│ Row │ cat │ prices │ vol │
├─────┼─────┼────────┼─────┤
│ 1   │ "a" │ 2.5    │ 50  │
│ 2   │ "b" │ 2.0    │ 20  │
│ 3   │ "c" │ 3.0    │ 30  │

如果您必须按日/月/等计算一些总数,您可能也会对此答案感兴趣。


You can use by:

df = DataFrame(
  cat = ["a", "b", "c","a"],
  prices = [1,2,3,4],
  vol    = [10,20,30,40],
)

df2 = by(df, :cat) do sub
      t = DataFrame(prices=mean(sub[:prices]), vol=sum(sub[:vol]))
end

df2

3×3 DataFrames.DataFrame
│ Row │ cat │ prices │ vol │
├─────┼─────┼────────┼─────┤
│ 1   │ "a" │ 2.5    │ 50  │
│ 2   │ "b" │ 2.0    │ 20  │
│ 3   │ "c" │ 3.0    │ 30  │

If you have to make some totals by day/months/etc you may be interested also in this so answer.

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