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汇编：如何将十六进制输入转换为十进制？(Assembly: How to convert hex input to decimal?)

 我在这个问题上找到了很多问题，但是，我无法运行我的代码。 我的程序应采用十六进制值，检查它是否是一个有效的十六进制字符，然后将十六进制值显示为十进制值。 如果它是小写十六进制字符，则需要将其转换为大写。 所有这些都需要循环。  
 除了将十六进制转换为十进制之外，我完成了所有这些操作。 我有程序中的代码我认为应该转换它，但它不会编译。 我将列出代码下面的编译器错误。 如果标签convert：中的代码被注释掉（除了最后一行，“jmp display”），程序将按原样运行，但显然不会将值显示为小数。  
 用nasme编译：“nasm -fbin getChar.asm -o getChar.com -l getChar.lst”  
 我在dosbox中运行程序。  
; This program gets a char from user and prints it out as a decimal 

    org 100h        ; program start point
section .data
    msgIn:  DB  13, 10, "Enter a Hex Digit: $"
    msgOut: DB  13, 10, "Decimal Value: $"
    msgOpt: DB  13, 10, "Enter another?(y or n): $"
    errMsg: DB  13, 10, "Illegal character, Enter 0..9 or A..F: $"
    HNUM:   DB  19H
    NUM:    DB  0
    D:      DB  10h
    H:      DB  16
    CNT:    DB  0

section .text

continue:               ; start of loop
        mov dx, msgIn   ; offset address of message to display
        mov ah, 9       ; print string function
        int 21h

        mov ah, 1       ; keyboard input sub-program
        int 21h         ; read character into al
        mov cl, al

legal:                  ; compare input to see if valid
        cmp cl, 48      ; cl < 0
        jl  end_if      ; yes, error msg
        cmp cl, 70      ; cl > F
        jg  check_case  ; yes, error msg

        jmp prntMsg2    ; print value of input

check_case:             ; check case of input
        cmp cl, 97      ; cl < a
        jl  end_if      ; yes, error msg
        cmp cl, 102     ; cl > f
        jg  end_if      ; yes, error msg

        jmp to_upper    ; need to send to function to convert to upper case
                        ; then pass to prntMsg2

to_upper:
        and al, 223 ; convert to upper case(0DFh)

        jmp prntMsg2

end_if:                 ; error message if invalid input
        mov ah, 9
        mov dx, errMsg  ; print error message
        int 21h

        jmp continue    ; get a new value

prntMsg2:               ; print second message*****
        mov dx, msgOut  ; offset of second message
        mov ah, 9       ; print string function
        int 21h         ; display message

convert:
        mov cx, 00
        mov dx, 00

    L6: mov ax, 00
        mov al, [HNUM]
        div word [D]
        mov [HNUM], al

        mov bx, ax
        mov cl, 0
        mov ax, 1
    L5: 
        cmp cl, 00
        je L7
        mul word [H]
        sub cl, 1
        jmp L5
    L7: 
        mul bh
        add dx, ax
        add word [CNT], 1
        cmp word [HNUM], 0
        jg L6
        mov [NUM], dl

        jmp display

display:                ; display character
        mov dl, al
        mov ah, 2       ; print char function
        int 21h

        mov ah, 9       ; see if user wants to do it again
        mov dx, msgOpt
        int 21h

        mov ah, 1
        int 21h
        mov bl, al
        cmp bl, 'y'     ; bl = y
        jne exitPrg     ; no, end

        jmp continue    ; get a new value

exitPrg:                ; exit program
        mov ah, 4ch     ; exit to DOS function
        int 21h         ; see you later!
 
 上面的代码已经过编辑，现在可以编译和运行。 但是，它仍然没有正确地从十六进制转换为十进制。 它根本不显示值，只是空白。 如果输入一封信，即使是字母af，它也会挂断。 数字不会挂起，但仍不显示值。  
 现在我已经运行至少我可以修复它，但是，任何指导都表示赞赏。 感谢Gene让我开始运行。 

I have found many questions on this issue, however, I have not been able to get my code to run. My program should take a hex value, check to see if it is a valid hex character, then display the hex value as a decimal value. If it is a lower case hex character then it needs to be converted to upper case. All this needs to be in a loop. 
I have all of this done except for converting the hex to decimal. I have the code in the program I think should convert it, but it will not compile. I will list the compiler errors below the code. If the code in the label convert: is commented out(except for the last line, "jmp display") then the program will run as it should, but obviously will not show the value as a decimal. 
Compiling with nasme: "nasm -fbin getChar.asm -o getChar.com -l getChar.lst" 
I am running the program in dosbox.  
; This program gets a char from user and prints it out as a decimal 

    org 100h        ; program start point
section .data
    msgIn:  DB  13, 10, "Enter a Hex Digit: $"
    msgOut: DB  13, 10, "Decimal Value: $"
    msgOpt: DB  13, 10, "Enter another?(y or n): $"
    errMsg: DB  13, 10, "Illegal character, Enter 0..9 or A..F: $"
    HNUM:   DB  19H
    NUM:    DB  0
    D:      DB  10h
    H:      DB  16
    CNT:    DB  0

section .text

continue:               ; start of loop
        mov dx, msgIn   ; offset address of message to display
        mov ah, 9       ; print string function
        int 21h

        mov ah, 1       ; keyboard input sub-program
        int 21h         ; read character into al
        mov cl, al

legal:                  ; compare input to see if valid
        cmp cl, 48      ; cl < 0
        jl  end_if      ; yes, error msg
        cmp cl, 70      ; cl > F
        jg  check_case  ; yes, error msg

        jmp prntMsg2    ; print value of input

check_case:             ; check case of input
        cmp cl, 97      ; cl < a
        jl  end_if      ; yes, error msg
        cmp cl, 102     ; cl > f
        jg  end_if      ; yes, error msg

        jmp to_upper    ; need to send to function to convert to upper case
                        ; then pass to prntMsg2

to_upper:
        and al, 223 ; convert to upper case(0DFh)

        jmp prntMsg2

end_if:                 ; error message if invalid input
        mov ah, 9
        mov dx, errMsg  ; print error message
        int 21h

        jmp continue    ; get a new value

prntMsg2:               ; print second message*****
        mov dx, msgOut  ; offset of second message
        mov ah, 9       ; print string function
        int 21h         ; display message

convert:
        mov cx, 00
        mov dx, 00

    L6: mov ax, 00
        mov al, [HNUM]
        div word [D]
        mov [HNUM], al

        mov bx, ax
        mov cl, 0
        mov ax, 1
    L5: 
        cmp cl, 00
        je L7
        mul word [H]
        sub cl, 1
        jmp L5
    L7: 
        mul bh
        add dx, ax
        add word [CNT], 1
        cmp word [HNUM], 0
        jg L6
        mov [NUM], dl

        jmp display

display:                ; display character
        mov dl, al
        mov ah, 2       ; print char function
        int 21h

        mov ah, 9       ; see if user wants to do it again
        mov dx, msgOpt
        int 21h

        mov ah, 1
        int 21h
        mov bl, al
        cmp bl, 'y'     ; bl = y
        jne exitPrg     ; no, end

        jmp continue    ; get a new value

exitPrg:                ; exit program
        mov ah, 4ch     ; exit to DOS function
        int 21h         ; see you later!
 
The code above has been edited and now compiles and runs. However, it is still not doing the conversion from hex to decimal correctly. It simply doesn't display a value, just blank. It will also hang up if a letter is entered, even a letter a-f. A number does not hang it up, but still a value is not displayed. 
Now that I have it running at least I can work on fixing it, however, any guidance is appreciated. Thanks Gene for getting me up and running.

原文：https://stackoverflow.com/questions/21870702

更新时间：2023-09-13 12:09

最满意答案

delete from a
where id not in
(
    select * from 
    (
      select a.id
      from ab
      join a on (ab.a=a.id)
      join b on (ab.b=b.id)
      where a.pid=b.pid
    ) x
);

delete from b
where id not in
(
    select * from 
    (
      select b.id
      from ab
      join a on (ab.a=a.id)  
      join b on (ab.b=b.id)
      where a.pid=b.pid
    ) x
);

delete ab from ab
left join a on ab.a = a.id
left join b on ab.b = b.id
where a.pid <> b.pid
or a.id is null 
or b.id is null;
 
 SQLFiddle演示 

delete from a
where id not in
(
    select * from 
    (
      select a.id
      from ab
      join a on (ab.a=a.id)
      join b on (ab.b=b.id)
      where a.pid=b.pid
    ) x
);

delete from b
where id not in
(
    select * from 
    (
      select b.id
      from ab
      join a on (ab.a=a.id)  
      join b on (ab.b=b.id)
      where a.pid=b.pid
    ) x
);

delete ab from ab
left join a on ab.a = a.id
left join b on ab.b = b.id
where a.pid <> b.pid
or a.id is null 
or b.id is null;
 
SQLFiddle demo

汇编：如何将十六进制输入转换为十进制？(Assembly: How to convert hex input to decimal?)

最满意答案

SQLFiddle演示

SQLFiddle demo

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