“官方”将组件部署到GAC的方式？(“Official” Way to deploy Assemblies into the GAC?)

 我认为使用scanf（）进行所需的验证时会遇到问题。 首先扫描一个字符串，然后将其转换为数字，你会做得更好。 但是scanf（）对于char字符串扫描是危险的，因为它的输入长度不受限制，你必须为它提供指向有限长度输入缓冲区的指针。 最好使用fgets（），它允许您限制输入缓冲区长度。 
 
#include <stdio.h>
int main(int argc, char **argv)
{
    double num=-1;
    char input[80]; // arbitrary size buffer
    char* cp, badc; // badc is for detecting extraneous chars in the input
    int n;
    printf("Enter a positive number:");
    while (num < 0)
    {
        cp = fgets(input, sizeof(input), stdin);
        if (cp == input)
        {
            n = sscanf(input, "%lf %c", &num, &badc);
            if (n != 1) // if badc captured an extraneous char
            {
                printf("Error! Please enter a number:");
                num = -1;
            }
            else if (num < 0)
                printf("Error! Please enter a POSITIVE number:");
        }
    }

    printf("num = %f\n", num);

    return 0;
}

I think you'll have problems doing the validation you want using just scanf(). You'll do better to first scan in a string and then convert it to a numeric. But scanf() is dangerous for scanning in char strings, since its input length is not limited and you have to provide it a pointer to a finite-length input buffer. Better to use fgets(), which allows you to limit the input buffer length.
 
#include <stdio.h>
int main(int argc, char **argv)
{
    double num=-1;
    char input[80]; // arbitrary size buffer
    char* cp, badc; // badc is for detecting extraneous chars in the input
    int n;
    printf("Enter a positive number:");
    while (num < 0)
    {
        cp = fgets(input, sizeof(input), stdin);
        if (cp == input)
        {
            n = sscanf(input, "%lf %c", &num, &badc);
            if (n != 1) // if badc captured an extraneous char
            {
                printf("Error! Please enter a number:");
                num = -1;
            }
            else if (num < 0)
                printf("Error! Please enter a POSITIVE number:");
        }
    }

    printf("num = %f\n", num);

    return 0;
}