Groovy正则表达式/模式匹配(Groovy regex/pattern matching)

 正如iainn所评论的问题是，PHP服务器在加载后缓存文件，而不是在第二次需要时从光盘重新调用文件，而是从它的内存缓存中调用它。 
 
 如你所说： 
 
 
 
 “文件内容发生变化” 
 
 
 那么问题是新内容没有传递给脚本，而是使用旧内容的内存 。 
 
 因此，调用clearstatcache()强制清除缓存的文件数据。 这应该在写入新数据以更新文件之后，以及在第二次调用文件之前放置。 
 
 如果这不起作用，则文件数据可以缓存在其路由中的其他位置。 
 
<?php

    $oldValue = require 'file.php';
    $now = new DateTime();
    $handle = fopen('file.php', "w");
    fputs($handle, "<?php\nreturn '" . $now->format('Y-m-d H:i:s') . "';");
    fclose($handle);
    clearstatcache();           // THIS line should help you 
    $newValue = require 'file.php';

    echo "Old value: $oldValue ";
    echo "New value: $newValue ";
?>
 
 
 
 
 正如iainn所述， opcache_invalidate()可能是一个更具体/更不通用的解决方案。 
 

As commented by iainn The issue is that the PHP server is caching the file once it's loaded and is not re-calling the file from disc on the second require, instead calling it from it's memory cache. 
 
As you have stated that:
 
 
 
"the content of the file changes "
 
 
then the issue is the new contents are not passed to the script, instead using the memory of the older contents.
 
Therefore call clearstatcache() to force clear the cached file data. This should be placed after the new data is written to update the file, and before the file is called for a second time.
 
If this does not work then the file data may be cached elsewhere in its route.
 
<?php

    $oldValue = require 'file.php';
    $now = new DateTime();
    $handle = fopen('file.php', "w");
    fputs($handle, "<?php\nreturn '" . $now->format('Y-m-d H:i:s') . "';");
    fclose($handle);
    clearstatcache();           // THIS line should help you 
    $newValue = require 'file.php';

    echo "Old value: $oldValue ";
    echo "New value: $newValue ";
?>
 
 
 
 
As also commented by iainn opcache_invalidate()may be a more specific/less general solution for you.