首页 \ 问答 \ 使用golang频道。(using golang channels. GETTING “all goroutines are asleep - deadlock!”)

使用golang频道。(using golang channels. GETTING “all goroutines are asleep - deadlock!”)

iam目前正在玩例程,频道和sync.WaitGroup。 我知道waitgroup用于等待所有go例程根据天气wg完成.Done()被调用足够的时间来取消wg.Add()中设置的值。 我写了一小段代码试图在golang操场上测试这个。 显示如下

var channel chan int
var wg sync.WaitGroup


func main() {

  channel := make(chan int)
  mynums := []int{1,2,3,4,5,6,7,8,9} 
  wg.Add(1)

  go addStuff(mynums)
  wg.Wait()
  close(channel)
  recieveStuff(channel)
 }

 func addStuff(mynums []int) {

   for _, val := range mynums {
       channel <- val
   }
   wg.Done()
 }

 func recieveStuff(channel chan int) {
    for val := range channel{
    fmt.Println(val)
 }
} 

我遇到了死锁错误。 我试图等待路由返回wg.Wait()? 然后,关闭频道。 然后,将通道发送到recievestuff方法以输出切片中的值? 但它不起作用。 我已经尝试在循环之后在go例程中移动close()方法,因为我认为我可能一直在尝试关闭main()中的错误例程。 香港专业教育学院发现这个东西到目前为止来自java和c#相对混乱。 任何帮助表示赞赏。


iam currently playing around with go routines, channels and sync.WaitGroup. I know waitgroup is used to wait for all go routines to complete based on weather wg.Done() has been called enough times to derement the value set in wg.Add(). i wrote a small bit of code to try to test this in golang playground. show below

var channel chan int
var wg sync.WaitGroup


func main() {

  channel := make(chan int)
  mynums := []int{1,2,3,4,5,6,7,8,9} 
  wg.Add(1)

  go addStuff(mynums)
  wg.Wait()
  close(channel)
  recieveStuff(channel)
 }

 func addStuff(mynums []int) {

   for _, val := range mynums {
       channel <- val
   }
   wg.Done()
 }

 func recieveStuff(channel chan int) {
    for val := range channel{
    fmt.Println(val)
 }
} 

Iam getting a deadlock error. iam trying to wait on the routing to return with wg.Wait()? then, close the channel. Afterwards, send the channel to the recievestuff method to output the values in the slice? but it doesnt work. Ive tried moving the close() method inside the go routine after the loop also as i thought i may of been trying to close on the wrong routine in main(). ive found this stuff relatively confusing so far coming from java and c#. Any help is appreciated.


原文:https://stackoverflow.com/questions/39576130
更新时间:2021-08-02 11:08

最满意答案

如果我理解正确,您使用的是cancan的authorize_resourceload_and_authorize_resource控制器帮助程序,它根据控制器操作名称计算用户能力。

但是,对所有操作使用此帮助程序并不是必须的。 您可以跳过具有复杂能力逻辑和手动检查能力的操作。

例如:

class ParticipationsController < ApplicationController
  authorize_resource except: :create # skiping `authorize_resource` for `create` action

  # ...

  def create
    if creator_adds_someone_to_event?
      authorize! :add_to, @event
    end

    if user_signs_up_for_event?
      authorize! :sign_up_for, @event
    end
    # ...
  end

因此,您可以在同一控制器操作中检查许多不同的功能。 只需禁用该操作的默认cancancan's行为即可。


If I understand correctly, you are using cancan's authorize_resource or load_and_authorize_resource controller helper that calculates user abilities based on controller actions names.

But it's not obligatory to use this helper for all actions. You can skip it for actions having complex ability logic and check abilities manually.

For example:

class ParticipationsController < ApplicationController
  authorize_resource except: :create # skiping `authorize_resource` for `create` action

  # ...

  def create
    if creator_adds_someone_to_event?
      authorize! :add_to, @event
    end

    if user_signs_up_for_event?
      authorize! :sign_up_for, @event
    end
    # ...
  end

So, you can check many different abilities in the same controller action. Just disable default cancancan's behaviour for the action.

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