首页 \ 问答 \ 如何通过当前登录的用户ID来解析ui-router状态的阻塞?(How to pass currently signed in user id to resolve block in ui-router state? (AngularJS))

如何通过当前登录的用户ID来解析ui-router状态的阻塞?(How to pass currently signed in user id to resolve block in ui-router state? (AngularJS))

我正在尝试将当前已登录的用户传递到“用户”状态的解析块(我正在使用ui-router),因此登录后,用户将在... / users /的URL中:ID。

其他路由嵌套在内:用户路由,所以这似乎是我最合乎逻辑的路径(我可能错了)。

我在这里使用angular_devise所以我应该能够通过Auth从API中提取:id,但是我遇到了一些麻烦。

(包括下面其他可能的相关文件。)

App.js

$stateProvder
  .state('users', { 
      url: '/users/{id}', 
      templateUrl: 'home/_home.html',
      controller: 'MainCtrl',
      resolve: {
          userPromise: ['$stateParams', 'users', 'Auth', function($stateParams, users, Auth) {
            return users.get(
                Auth.currentUser().then(function (user) {
                return user.id;
            })
          );
      }]
    }
  })

Users.js

.factory('users', ['$http', function($http) {
    var u = {
        userArray: []
    };
    u.get = function(id) {
        return $http.get('/users/' + id + '.json').then(function(res) {
            console.log('request: ', res.data);
            angular.copy(res.data, u.userArray);

        });
    };
    return u;
}]);

Users_controller.rb

class UsersController < ApplicationController
    def show
        @user = User.find(params[:id])
        authorize @user
        respond_with @user
    end
end

NavCtrl.js

.controller('NavCtrl', [
    '$scope',
    'Auth',
    function($scope, Auth) {
        $scope.signedIn = Auth.isAuthenticated;
        $scope.logout = Auth.logout;

        Auth.currentUser().then(function (user) {
            $scope.user = user;
        });

        $scope.$on('devise:new-registration', function (e, user) {
            $scope.user = user;
        });

        $scope.$on('devise:login', function (e, user) {
            $scope.user = user;
        });

        $scope.$on('devise:logout', function (e, user) {
            $scope.user = {};
        });
    }])
;

仅供参考。 $ http请求被发送到rails后端。

如果有人能告诉我可能做错了什么,我将非常感激。


I'm trying to pass the currently signed-in user to the resolve block of a 'user' state (I'm using ui-router), so upon sign-in, user will be in url of .../users/:id.

Other routes are nested inside :user route, so this seems the most logical path to me (I may be wrong).

I'm using angular_devise here so i should be able to extract the :id from from API via Auth, but I'm running into some trouble.

(Included other possible relevant files below.)

App.js

$stateProvder
  .state('users', { 
      url: '/users/{id}', 
      templateUrl: 'home/_home.html',
      controller: 'MainCtrl',
      resolve: {
          userPromise: ['$stateParams', 'users', 'Auth', function($stateParams, users, Auth) {
            return users.get(
                Auth.currentUser().then(function (user) {
                return user.id;
            })
          );
      }]
    }
  })

Users.js

.factory('users', ['$http', function($http) {
    var u = {
        userArray: []
    };
    u.get = function(id) {
        return $http.get('/users/' + id + '.json').then(function(res) {
            console.log('request: ', res.data);
            angular.copy(res.data, u.userArray);

        });
    };
    return u;
}]);

Users_controller.rb

class UsersController < ApplicationController
    def show
        @user = User.find(params[:id])
        authorize @user
        respond_with @user
    end
end

NavCtrl.js

.controller('NavCtrl', [
    '$scope',
    'Auth',
    function($scope, Auth) {
        $scope.signedIn = Auth.isAuthenticated;
        $scope.logout = Auth.logout;

        Auth.currentUser().then(function (user) {
            $scope.user = user;
        });

        $scope.$on('devise:new-registration', function (e, user) {
            $scope.user = user;
        });

        $scope.$on('devise:login', function (e, user) {
            $scope.user = user;
        });

        $scope.$on('devise:logout', function (e, user) {
            $scope.user = {};
        });
    }])
;

FYI. $http request is being sent to a rails backend.

I would be very grateful if anyone can advise what i might be doing wrong.


原文:https://stackoverflow.com/questions/36011645
更新时间:2023-05-02 07:05

最满意答案

您可以尝试在try块中进行转换,并忽略catch块中的异常。 (按照你的建议continue循环)。 它会工作。

另一种方法,不使用异常处理;

确定String是否是Java中的整数

如何检查String中的String是否为数字

还有更多。


You can try to convert in a try block, and ignore the exception in the catch block. (Just continue the loop, like you suggested). It will work.

Another method, without making use of exceptions handling;

Determine if a String is an Integer in Java

How to check if a String is numeric in Java

And there are many more.

相关问答

更多

相关文章

更多

最新问答

更多
  • 获取MVC 4使用的DisplayMode后缀(Get the DisplayMode Suffix being used by MVC 4)
  • 如何通过引用返回对象?(How is returning an object by reference possible?)
  • 矩阵如何存储在内存中?(How are matrices stored in memory?)
  • 每个请求的Java新会话?(Java New Session For Each Request?)
  • css:浮动div中重叠的标题h1(css: overlapping headlines h1 in floated divs)
  • 无论图像如何,Caffe预测同一类(Caffe predicts same class regardless of image)
  • xcode语法颜色编码解释?(xcode syntax color coding explained?)
  • 在Access 2010 Runtime中使用Office 2000校对工具(Use Office 2000 proofing tools in Access 2010 Runtime)
  • 从单独的Web主机将图像传输到服务器上(Getting images onto server from separate web host)
  • 从旧版本复制文件并保留它们(旧/新版本)(Copy a file from old revision and keep both of them (old / new revision))
  • 西安哪有PLC可控制编程的培训
  • 在Entity Framework中选择基类(Select base class in Entity Framework)
  • 在Android中出现错误“数据集和渲染器应该不为null,并且应该具有相同数量的系列”(Error “Dataset and renderer should be not null and should have the same number of series” in Android)
  • 电脑二级VF有什么用
  • Datamapper Ruby如何添加Hook方法(Datamapper Ruby How to add Hook Method)
  • 金华英语角.
  • 手机软件如何制作
  • 用于Android webview中图像保存的上下文菜单(Context Menu for Image Saving in an Android webview)
  • 注意:未定义的偏移量:PHP(Notice: Undefined offset: PHP)
  • 如何读R中的大数据集[复制](How to read large dataset in R [duplicate])
  • Unity 5 Heighmap与地形宽度/地形长度的分辨率关系?(Unity 5 Heighmap Resolution relationship to terrain width / terrain length?)
  • 如何通知PipedOutputStream线程写入最后一个字节的PipedInputStream线程?(How to notify PipedInputStream thread that PipedOutputStream thread has written last byte?)
  • python的访问器方法有哪些
  • DeviceNetworkInformation:哪个是哪个?(DeviceNetworkInformation: Which is which?)
  • 在Ruby中对组合进行排序(Sorting a combination in Ruby)
  • 网站开发的流程?
  • 使用Zend Framework 2中的JOIN sql检索数据(Retrieve data using JOIN sql in Zend Framework 2)
  • 条带格式类型格式模式编号无法正常工作(Stripes format type format pattern number not working properly)
  • 透明度错误IE11(Transparency bug IE11)
  • linux的基本操作命令。。。