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$ _FILES和cURL的问题(Problem with $_FILES and cURL)

 我在通过cURL发送$ _FILES时遇到了一些麻烦 - 使用以下代码将文件传输好了，但是我不可能获得文件的名称和类型，实际上一旦$ _FILES到达目的地他们的类型存储为“application / octet-stream” - 我做错了什么！？ 
 

 $count=count($_FILES['thefile']['tmp_name']);

 for($i=0;$i<$count;$i++) {
  if(!empty($_FILES['thefile']['name'][$i])) {
   $postargs[$i] = '@'.$_FILES['thefile']['tmp_name'][$i];
  }
 }


 $header = array("Content-type: multipart/form-data");
 $ch = curl_init('http://localhost/curl/rec.php');
 curl_setopt($ch,CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)");  
 curl_setopt($ch,CURLOPT_RETURNTRANSFER, false); 
 curl_setopt($ch,CURLOPT_ENCODING,"");
 curl_setopt($ch,CURLOPT_HTTPHEADER,$header);
 curl_setopt($ch,CURLOPT_FOLLOWLOCATION, TRUE);
 curl_setopt($ch,CURLOPT_POST,TRUE);
 curl_setopt($ch,CURLOPT_POSTFIELDS,$postargs);
 curl_exec($ch);
 curl_close($ch)


I'm having some trouble sending $_FILES by cURL - the files get transferred alright using the following code, however it is impossible for me to get the name, and type of the file, in fact once the $_FILES reach their destination their type is stored as "application/octet-stream" - what am I doing wrong!? 
 

 $count=count($_FILES['thefile']['tmp_name']);

 for($i=0;$i<$count;$i++) {
  if(!empty($_FILES['thefile']['name'][$i])) {
   $postargs[$i] = '@'.$_FILES['thefile']['tmp_name'][$i];
  }
 }


 $header = array("Content-type: multipart/form-data");
 $ch = curl_init('http://localhost/curl/rec.php');
 curl_setopt($ch,CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)");  
 curl_setopt($ch,CURLOPT_RETURNTRANSFER, false); 
 curl_setopt($ch,CURLOPT_ENCODING,"");
 curl_setopt($ch,CURLOPT_HTTPHEADER,$header);
 curl_setopt($ch,CURLOPT_FOLLOWLOCATION, TRUE);
 curl_setopt($ch,CURLOPT_POST,TRUE);
 curl_setopt($ch,CURLOPT_POSTFIELDS,$postargs);
 curl_exec($ch);
 curl_close($ch)


原文：https://stackoverflow.com/questions/3223478
更新时间：2023-10-24 08:10

最满意答案

 请对您的代码和脚本进行一些更改。我认为下面的代码可能对您有用。 
 

<head><script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">

$(document).ready(function() {

$("#email").change(function() {

        var pass = $("#Repeat").val();
        var email = $("#email").val();
        if (pass === email) {
            $(".bar1").html("email match");
        }
else {
            $(".bar1").html("<span style='color:goldenrod;font-size: 11px;margin-left: 21px;font-family: Arial,Helvetica,sans-serif;'>email does not Match.</span>");
        }
    });
$("#Repeat").change(function() {
var pass = $("#Repeat").val();
        var email = $("#email").val();
        if (pass === email) {
            $(".bar2").html("email match");
             $(".bar1").hide();
        }
        else {
            $(".bar2").html("<span style='color:goldenrod;font-size: 11px;margin-left: 21px;font-family: Arial,Helvetica,sans-serif;'>email does not Match.</span>");

        }
    });

});
</script>
</head>

 

 并在您的html部分进行一些更改，如更改类名和ID，如下所示。 
 

<form>


<div class="input-container">
 <input type="text" id="Username" required="required"/>
<label for="Username">@Username</label>
<div class="bar"></div>
  </div>
<div class="input-container">
<input type="email" id="email" required="required"/>
<label for="email">Email</label>
<div class="bar1"></div>
</div>
<div class="input-container">
<input type="email" id="Repeat" required="required"/>
<label for="Repeat email">Repeat Email</label>
<div class="bar2"></div>
</div>
<div class="button-container">
<button><span>Next</span></button>
</div>
</form>


please make some changes in your code and script.I think below code may be useful to you.
 

<head><script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">

$(document).ready(function() {

$("#email").change(function() {

        var pass = $("#Repeat").val();
        var email = $("#email").val();
        if (pass === email) {
            $(".bar1").html("email match");
        }
else {
            $(".bar1").html("<span style='color:goldenrod;font-size: 11px;margin-left: 21px;font-family: Arial,Helvetica,sans-serif;'>email does not Match.</span>");
        }
    });
$("#Repeat").change(function() {
var pass = $("#Repeat").val();
        var email = $("#email").val();
        if (pass === email) {
            $(".bar2").html("email match");
             $(".bar1").hide();
        }
        else {
            $(".bar2").html("<span style='color:goldenrod;font-size: 11px;margin-left: 21px;font-family: Arial,Helvetica,sans-serif;'>email does not Match.</span>");

        }
    });

});
</script>
</head>

 

and make some changes in your html section like changing class name and id as below.
 

<form>


<div class="input-container">
 <input type="text" id="Username" required="required"/>
<label for="Username">@Username</label>
<div class="bar"></div>
  </div>
<div class="input-container">
<input type="email" id="email" required="required"/>
<label for="email">Email</label>
<div class="bar1"></div>
</div>
<div class="input-container">
<input type="email" id="Repeat" required="required"/>
<label for="Repeat email">Repeat Email</label>
<div class="bar2"></div>
</div>
<div class="button-container">
<button><span>Next</span></button>
</div>
</form>

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