首页 \ 问答 \ 你如何向Facebook好友的收件箱发送消息[重复](How do you to send a message to facebook friend's inbox [duplicate])

你如何向Facebook好友的收件箱发送消息[重复](How do you to send a message to facebook friend's inbox [duplicate])

这个问题在这里已有答案:

如何将私人消息发送到朋友的收件箱,类似于Spotify如何将曲目发送到用户的朋友收件箱。 我做了一些研究,但我找不到任何API来实现这一点。


This question already has an answer here:

How do you send private messages to a friend's inbox similar to how Spotify sends tracks to a user's friends inbox. I have done some research but I have not been able to find any API to implement this.


原文:https://stackoverflow.com/questions/17856367
更新时间:2023-09-05 21:09

最满意答案

你会想使用m选项,它允许点匹配新行:

Donec sed odio dui. *Nullam id dolor id 
nibh ultricies vehicula ut*

正则表达式 str.match(/\*(.*)\*/m)[1]现场示例: http : str.match(/\*(.*)\*/m)[1]

你的表情会捕捉到第一个和最后一个*符号之间的文本,但是如果你想捕捉每一组*之间的所有文本,那么你会想让.*少一些贪婪

str.match(/\*(.*?)\*/m)[1]现场示例http://www.rubular.com/r/rBLOnwy3By

或者你可以告诉它简单地匹配所有非*字符,注意不需要m选项,因为一个新的行字符会被一个否定的[^*]字符类匹配:

str.match(/\*([^*]*)\*/)[1]现场示例http://www.rubular.com/r/dhQzZ58ZzM


You'll want to use the m option which allows the dot to match new lines:

Donec sed odio dui. *Nullam id dolor id 
nibh ultricies vehicula ut*

regex str.match(/\*(.*)\*/m)[1] Live example: http://www.rubular.com/r/11u9TreEOL

Your expression will capture the text between the first and last * symbol, but if you want to capture all text between each set of * then you'd want to make the .* less greedy like

str.match(/\*(.*?)\*/m)[1] Live example http://www.rubular.com/r/rBLOnwy3By

Or you could tell it to simply match all non * characters like, note the m option is not needed as a new line character would be matched by a the negated [^*] character class:

str.match(/\*([^*]*)\*/)[1] Live example http://www.rubular.com/r/dhQzZ58ZzM

相关问答

更多

相关文章

更多

最新问答

更多
  • 获取MVC 4使用的DisplayMode后缀(Get the DisplayMode Suffix being used by MVC 4)
  • 如何通过引用返回对象?(How is returning an object by reference possible?)
  • 矩阵如何存储在内存中?(How are matrices stored in memory?)
  • 每个请求的Java新会话?(Java New Session For Each Request?)
  • css:浮动div中重叠的标题h1(css: overlapping headlines h1 in floated divs)
  • 无论图像如何,Caffe预测同一类(Caffe predicts same class regardless of image)
  • xcode语法颜色编码解释?(xcode syntax color coding explained?)
  • 在Access 2010 Runtime中使用Office 2000校对工具(Use Office 2000 proofing tools in Access 2010 Runtime)
  • 从单独的Web主机将图像传输到服务器上(Getting images onto server from separate web host)
  • 从旧版本复制文件并保留它们(旧/新版本)(Copy a file from old revision and keep both of them (old / new revision))
  • 西安哪有PLC可控制编程的培训
  • 在Entity Framework中选择基类(Select base class in Entity Framework)
  • 在Android中出现错误“数据集和渲染器应该不为null,并且应该具有相同数量的系列”(Error “Dataset and renderer should be not null and should have the same number of series” in Android)
  • 电脑二级VF有什么用
  • Datamapper Ruby如何添加Hook方法(Datamapper Ruby How to add Hook Method)
  • 金华英语角.
  • 手机软件如何制作
  • 用于Android webview中图像保存的上下文菜单(Context Menu for Image Saving in an Android webview)
  • 注意:未定义的偏移量:PHP(Notice: Undefined offset: PHP)
  • 如何读R中的大数据集[复制](How to read large dataset in R [duplicate])
  • Unity 5 Heighmap与地形宽度/地形长度的分辨率关系?(Unity 5 Heighmap Resolution relationship to terrain width / terrain length?)
  • 如何通知PipedOutputStream线程写入最后一个字节的PipedInputStream线程?(How to notify PipedInputStream thread that PipedOutputStream thread has written last byte?)
  • python的访问器方法有哪些
  • DeviceNetworkInformation:哪个是哪个?(DeviceNetworkInformation: Which is which?)
  • 在Ruby中对组合进行排序(Sorting a combination in Ruby)
  • 网站开发的流程?
  • 使用Zend Framework 2中的JOIN sql检索数据(Retrieve data using JOIN sql in Zend Framework 2)
  • 条带格式类型格式模式编号无法正常工作(Stripes format type format pattern number not working properly)
  • 透明度错误IE11(Transparency bug IE11)
  • linux的基本操作命令。。。