首页 \ 问答 \ Facebook Canvas:redirect_uri不归应用程序所有(Facebook Canvas: redirect_uri is not owned by the application)

Facebook Canvas:redirect_uri不归应用程序所有(Facebook Canvas: redirect_uri is not owned by the application)

我正在尝试将facebook canvas集成到当前在localhost:8080上运行的Web应用程序localhost:8080运行该站点时它给了我这个错误。

API Error Code: 191
API Error Description: The specified URL is not owned by the application
Error Message: redirect_uri is not owned by the application.

这是我的应用程序设置。

在此处输入图像描述

我刚刚关注文档,这个错误出现了,

window.fbAsyncInit = function() {
                            FB
                                    .init({
                                        appId : 'myappIdHere', // App ID
                                        channelUrl : 'https://apps.facebook.com/mytestapp/', // Channel File
                                        status : true, // check login status
                                        cookie : true, // enable cookies to allow the server to access the session
                                        xfbml : true
                                    // parse XFBML
                                    });
                            FB.ui({
                                method : 'feed'
                            });
                        };
                        // Load the SDK Asynchronously
                        (function(d, s, id) {
                            var js, fjs = d.getElementsByTagName(s)[0];
                            if (d.getElementById(id)) {
                                return;
                            }
                            js = d.createElement(s);
                            js.id = id;
                            js.src = "//connect.facebook.net/en_US/all.js";
                            fjs.parentNode.insertBefore(js, fjs);
                        }(document, 'script', 'facebook-jssdk'));

I am trying to integrate facebook canvas on my web application that is currently running on localhost:8080 upon running the site it gave me this error.

API Error Code: 191
API Error Description: The specified URL is not owned by the application
Error Message: redirect_uri is not owned by the application.

And here is my app settings.

enter image description here

I was just following the documentation and this error showed up,

window.fbAsyncInit = function() {
                            FB
                                    .init({
                                        appId : 'myappIdHere', // App ID
                                        channelUrl : 'https://apps.facebook.com/mytestapp/', // Channel File
                                        status : true, // check login status
                                        cookie : true, // enable cookies to allow the server to access the session
                                        xfbml : true
                                    // parse XFBML
                                    });
                            FB.ui({
                                method : 'feed'
                            });
                        };
                        // Load the SDK Asynchronously
                        (function(d, s, id) {
                            var js, fjs = d.getElementsByTagName(s)[0];
                            if (d.getElementById(id)) {
                                return;
                            }
                            js = d.createElement(s);
                            js.id = id;
                            js.src = "//connect.facebook.net/en_US/all.js";
                            fjs.parentNode.insertBefore(js, fjs);
                        }(document, 'script', 'facebook-jssdk'));

原文:
更新时间:2022-05-25 09:05

最满意答案

虽然我没有看到运行您发布的示例代码的任何问题,但如果您在应用程序中看不到一致的结果,那么创建自己的滚动控制器并不是太棘手。 这是您可以使用的示例实现:

private class ScrollPositioner {
    private static final int SCROLL_DURATION = 20;
    private static final int DIR_UP = 1;
    private static final int DIR_DOWN = 2;

    int mTargetPosition = AdapterView.INVALID_POSITION;
    int mDirection = AdapterView.INVALID_POSITION;
    int mLastSeenPosition = AdapterView.INVALID_POSITION;
    int mExtraScroll;
    GridView mGrid;

    public ScrollPositioner(GridView grid) {
        mGrid = grid;
        mExtraScroll = ViewConfiguration.get(mGrid.getContext()).getScaledFadingEdgeLength();
    }

    Handler mHandler = new Handler();
    Runnable mScroller = new Runnable() {
        public void run() {
            int firstPos = mGrid.getFirstVisiblePosition();
            switch(mDirection) {
            case DIR_UP: {
                if (firstPos == mLastSeenPosition) {
                    // No new views, let things keep going.
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                    return;
                }

                final View firstView = mGrid.getChildAt(0);
                if (firstView == null) {
                    return;
                }
                final int firstViewTop = firstView.getTop();
                final int extraScroll = firstPos > 0 ? mExtraScroll : mGrid.getPaddingTop();

                mGrid.smoothScrollBy(firstViewTop - extraScroll, SCROLL_DURATION);

                mLastSeenPosition = firstPos;

                if (firstPos > mTargetPosition) {
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                }
                break;
            }

            case DIR_DOWN: {
                final int lastViewIndex = mGrid.getChildCount() - 1;
                final int lastPos = firstPos + lastViewIndex;

                if (lastViewIndex < 0) {
                    return;
                }

                if (lastPos == mLastSeenPosition) {
                    // No new views, let things keep going.
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                    return;
                }

                final View lastView = mGrid.getChildAt(lastViewIndex);
                final int lastViewHeight = lastView.getHeight();
                final int lastViewTop = lastView.getTop();
                final int lastViewPixelsShowing = mGrid.getHeight() - lastViewTop;
                final int extraScroll = lastPos < mGrid.getAdapter().getCount() - 1 ? mExtraScroll : mGrid.getPaddingBottom();

                mGrid.smoothScrollBy(lastViewHeight - lastViewPixelsShowing + extraScroll, SCROLL_DURATION);

                mLastSeenPosition = lastPos;
                if (lastPos < mTargetPosition) {
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                }
                break;
            }

            default:
                break;
            }
        }
    };

    public void scrollToPosition(int position) {
        mTargetPosition = position;
        mLastSeenPosition = AdapterView.INVALID_POSITION;

        if(position < mGrid.getFirstVisiblePosition()) {
            mDirection = DIR_UP;
        } else if (position > mGrid.getLastVisiblePosition()) {
            mDirection = DIR_DOWN;
        } else {
            return;
        }
        mHandler.post(mScroller);
    }
}

这是您链接的示例的片段,其中包括此新类的位置,以代替框架实现进行滚动:

GridView g;
boolean t= false;
@Override
public void onBackPressed() {
    //Instantiate and attach the custom positioner
    if(mPositioner == null) {
        mPositioner = new ScrollPositioner(g);
    }
    //Use the custom object to scroll the view
    mPositioner.scrollToPosition(0);
    if(t) {
        super.onBackPressed();
    }
    else {
        t = true;
    }
}

如果要添加一个功能,即使滚动方向向下,所选位置也始终滚动到顶部,您可以这样做。 这不是框架实现的目的 ,但您可以通过在DIR_DOWN添加一些代码来继续滚动直到第一个可见位置与目标匹配(如DIR_UP )。 您还必须注意滚动在位置到达顶部之前结束的情况,因此在您永远不会得到不同结果的情况下,您不会经常发布处理程序。

HTH


While I'm not seeing any issues running the example code you posted, if you're not seeing consistent results in your application it's not too tricky to create your own scroll controller. Here's an example implementation you could use:

private class ScrollPositioner {
    private static final int SCROLL_DURATION = 20;
    private static final int DIR_UP = 1;
    private static final int DIR_DOWN = 2;

    int mTargetPosition = AdapterView.INVALID_POSITION;
    int mDirection = AdapterView.INVALID_POSITION;
    int mLastSeenPosition = AdapterView.INVALID_POSITION;
    int mExtraScroll;
    GridView mGrid;

    public ScrollPositioner(GridView grid) {
        mGrid = grid;
        mExtraScroll = ViewConfiguration.get(mGrid.getContext()).getScaledFadingEdgeLength();
    }

    Handler mHandler = new Handler();
    Runnable mScroller = new Runnable() {
        public void run() {
            int firstPos = mGrid.getFirstVisiblePosition();
            switch(mDirection) {
            case DIR_UP: {
                if (firstPos == mLastSeenPosition) {
                    // No new views, let things keep going.
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                    return;
                }

                final View firstView = mGrid.getChildAt(0);
                if (firstView == null) {
                    return;
                }
                final int firstViewTop = firstView.getTop();
                final int extraScroll = firstPos > 0 ? mExtraScroll : mGrid.getPaddingTop();

                mGrid.smoothScrollBy(firstViewTop - extraScroll, SCROLL_DURATION);

                mLastSeenPosition = firstPos;

                if (firstPos > mTargetPosition) {
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                }
                break;
            }

            case DIR_DOWN: {
                final int lastViewIndex = mGrid.getChildCount() - 1;
                final int lastPos = firstPos + lastViewIndex;

                if (lastViewIndex < 0) {
                    return;
                }

                if (lastPos == mLastSeenPosition) {
                    // No new views, let things keep going.
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                    return;
                }

                final View lastView = mGrid.getChildAt(lastViewIndex);
                final int lastViewHeight = lastView.getHeight();
                final int lastViewTop = lastView.getTop();
                final int lastViewPixelsShowing = mGrid.getHeight() - lastViewTop;
                final int extraScroll = lastPos < mGrid.getAdapter().getCount() - 1 ? mExtraScroll : mGrid.getPaddingBottom();

                mGrid.smoothScrollBy(lastViewHeight - lastViewPixelsShowing + extraScroll, SCROLL_DURATION);

                mLastSeenPosition = lastPos;
                if (lastPos < mTargetPosition) {
                    mHandler.postDelayed(mScroller, SCROLL_DURATION);
                }
                break;
            }

            default:
                break;
            }
        }
    };

    public void scrollToPosition(int position) {
        mTargetPosition = position;
        mLastSeenPosition = AdapterView.INVALID_POSITION;

        if(position < mGrid.getFirstVisiblePosition()) {
            mDirection = DIR_UP;
        } else if (position > mGrid.getLastVisiblePosition()) {
            mDirection = DIR_DOWN;
        } else {
            return;
        }
        mHandler.post(mScroller);
    }
}

Here's a snippet from the example you linked that includes where this new class to do the scrolling in place of the framework implementation:

GridView g;
boolean t= false;
@Override
public void onBackPressed() {
    //Instantiate and attach the custom positioner
    if(mPositioner == null) {
        mPositioner = new ScrollPositioner(g);
    }
    //Use the custom object to scroll the view
    mPositioner.scrollToPosition(0);
    if(t) {
        super.onBackPressed();
    }
    else {
        t = true;
    }
}

If you want to add a feature where the selected position is always scrolled to the top even when the scrolling direction is down, you could do that. This is not something the framework's implementation is designed to do, but you could accomplish it by adding some code in DIR_DOWN to continue scrolling until the first visible position matches target (like DIR_UP does). You must also beware of the case where the scrolling ends before the position reaches the top, so you aren't constantly posting the handler in cases where you will never get a different result.

HTH

相关问答

更多