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doOnError不会捕获异常(doOnError does not catch the exception)

 我刚刚开始使用RxJava，但也许还没有点击。  
 1。  
Integer[] items = {1, 2, 3, 0, 0, 4, 5, 6, 1};
Observable.from(items)
        .map(this::invert)
        .subscribe(i -> Log.d(LOG_TAG, "Inverted: " + i), t -> Log.d(LOG_TAG, "Error: " + t.getMessage()));
 
 2。  
Integer[] items = {1, 2, 3, 0, 0, 4, 5, 6, 1};
Observable.from(items)
        .map(this::invert)
        .doOnError(t -> Log.d(LOG_TAG, "Error: " + t.getMessage()))
        .doOnNext(i -> Log.d(LOG_TAG, "Inverted: " + i))
        .subscribe();
 
 invert功能：  
int invert(int i) {
    return 1 / i;
}
 
 第一个正常执行，当抛出异常时，执行onError 。 但另一方面，第二个不起作用，所以异常一直抛到调用方法。  
 两个代码块之间有什么区别？ 

I am just getting started with RxJava, but maybe something did not click yet. 
1. 
Integer[] items = {1, 2, 3, 0, 0, 4, 5, 6, 1};
Observable.from(items)
        .map(this::invert)
        .subscribe(i -> Log.d(LOG_TAG, "Inverted: " + i), t -> Log.d(LOG_TAG, "Error: " + t.getMessage()));
 
2. 
Integer[] items = {1, 2, 3, 0, 0, 4, 5, 6, 1};
Observable.from(items)
        .map(this::invert)
        .doOnError(t -> Log.d(LOG_TAG, "Error: " + t.getMessage()))
        .doOnNext(i -> Log.d(LOG_TAG, "Inverted: " + i))
        .subscribe();
 
The invert function: 
int invert(int i) {
    return 1 / i;
}
 
The first executes normally, and when the exception is thrown the onError is executed. But on the other hand, the second does not work, so the exception is thrown all the way up to the calling method.  
What is the difference between the two blocks of code? 

原文：https://stackoverflow.com/questions/41508408

更新时间：2023-11-09 15:11

最满意答案

 您可以逐行扫描文件的内容并使用以下代码进行处理：  
public class MyProj03 {

public static void main(String[] args) throws IOException {
File file = new File("p3text.txt");

try {
    Scanner scanner = new Scanner(file);
    while (scanner.hasNextLine()) {
        String line = scanner.nextLine();
        Person one = new Person();
        one.parseCommaDelim(line);
    }
    scanner.close();
} catch (FileNotFoundException e) {
    e.printStackTrace();
}
}
 
 我还建议你改变片段代码：  
    Person instance = new Person();
    instance.name = tokens[0];
    instance.age = Integer.parseInt(tokens[1]); //ArrayIndexOutOfBoundsException error 
    instance.city = tokens[2];
    instance.sibCount = Integer.parseInt(tokens[3]);
 
 对此：  
   Person instance = new Person();
   instance.name = tokens[0];
   instance.age = Integer.parseInt(tokens[1].trim()); //ArrayIndexOutOfBoundsException error 
   instance.city = tokens[2];
   instance.sibCount = Integer.parseInt(tokens[3].trim());

You can scan file's content line by line and process with this code: 
public class MyProj03 {

public static void main(String[] args) throws IOException {
File file = new File("p3text.txt");

try {
    Scanner scanner = new Scanner(file);
    while (scanner.hasNextLine()) {
        String line = scanner.nextLine();
        Person one = new Person();
        one.parseCommaDelim(line);
    }
    scanner.close();
} catch (FileNotFoundException e) {
    e.printStackTrace();
}
}
 
also I recommend you to change the fragment codes : 
    Person instance = new Person();
    instance.name = tokens[0];
    instance.age = Integer.parseInt(tokens[1]); //ArrayIndexOutOfBoundsException error 
    instance.city = tokens[2];
    instance.sibCount = Integer.parseInt(tokens[3]);
 
to this: 
   Person instance = new Person();
   instance.name = tokens[0];
   instance.age = Integer.parseInt(tokens[1].trim()); //ArrayIndexOutOfBoundsException error 
   instance.city = tokens[2];
   instance.sibCount = Integer.parseInt(tokens[3].trim());

doOnError不会捕获异常(doOnError does not catch the exception)

最满意答案

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