作为参数的函数(Functions as arguments)

 我发现自己处于需要将函数作为参数传递给另一个函数的情况。 
 
int callSomeFunction(int &func){
  func();
}
 
 如果它有任何区别， callSomeFunction是一个类成员。 
 
class A{
  A(){}
  int callSomeFunction(int &func){
    func();
  }
  ~A(){}
};
A a();
a.callSomeFunction(func);
 
 理想情况下， callSomeFunction可以采用任何类型的功能。 
 
template<typename T>
T callSomeFunction(T &func){
  func();
}
 
 我已经尝试了很多事情，谷歌搜索几个小时，所有标准的东西。 我找到了这些东西，但发现它们对于实现这一目标的最佳方式是不确定的，或者更恰当地说是最有效的。 
 
 资源1 
 
 资源2 
 
 我喜欢在适用的地方使用引用而不是指针，主要是因为它们在任何情况下都不是记忆混乱，也不是语法混乱。 但是，如果指针更适用或更好的解决方案，我也欢迎这些答案。 谢谢你，如果你认为它可能对其他人也有帮助，那么对于如何改进这个问题的任何帮助或指示也会受到赞赏。 

I have found myself to be in a situation where I need to pass a function to another function as an argument.
 
int callSomeFunction(int &func){
  func();
}
 
If it makes any difference, callSomeFunction is a class member.
 
class A{
  A(){}
  int callSomeFunction(int &func){
    func();
  }
  ~A(){}
};
A a();
a.callSomeFunction(func);
 
Ideally, callSomeFunction would be able to take any kind of function.
 
template<typename T>
T callSomeFunction(T &func){
  func();
}
 
I have tried many things to do this, Googled for several hours, all the standard stuff. I found these things but found them inconclusive as to the best way to accomplish this, or more appropriately the most efficient.
 
Resource 1
 
Resource 2
 
I like to use references over pointers where applicable, mostly because they are not a memory mess nor a syntactical mess in any cases. However, if pointers would be more applicable or a better solution, I welcome those answers as well. Thank you, any help or pointers on how to improve the question are also appreciated should you think it may help other people as well.

原文：https://stackoverflow.com/questions/27117468