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参考数据类成员访问者模式(reference data class member visitor pattern)

 我有一个容器类，它有一个名为DataStore的普通旧数据类型。 此数据存储将传递给访问者。他们共享一个副本，因为访问者可以看到容器执行的任何更新。  
class xyz
{
    //Plain Old Datatype
    typedef struct DataStore
    {
        //add any new required data by any test here
        bool    _detectorConnectionStatus;
        DataStore():_detectorConnectionStatus(false){}
    }DataStore;

    DataStore _dataStore;

    typedef struct visitorData
    {
        DataStore& dataStore;
        visitorData(DataStore data):dataStore(data){}
    }visitorData;

    //data to be sent to visitor
    visitorData _visitorData;
};

xyz::xyz():_visitorData(_dataStore)
{
}

class IVisitor
{
private:
struct DataStore* dataStore;
public:
//get the data,no check for validity of data performed
 void visit(struct DataStore& dataStore){};
//process the data
virtual void process() = 0;
};
 
 代码编译但是有更好/更清洁的方法吗？ 

I have a container class that has a plain old datatype called DataStore. This data store will be passed to visitor.They share a single copy since any updated performed by the container are to be seen by visitor. 
class xyz
{
    //Plain Old Datatype
    typedef struct DataStore
    {
        //add any new required data by any test here
        bool    _detectorConnectionStatus;
        DataStore():_detectorConnectionStatus(false){}
    }DataStore;

    DataStore _dataStore;

    typedef struct visitorData
    {
        DataStore& dataStore;
        visitorData(DataStore data):dataStore(data){}
    }visitorData;

    //data to be sent to visitor
    visitorData _visitorData;
};

xyz::xyz():_visitorData(_dataStore)
{
}

class IVisitor
{
private:
struct DataStore* dataStore;
public:
//get the data,no check for validity of data performed
 void visit(struct DataStore& dataStore){};
//process the data
virtual void process() = 0;
};
 
The code compiles but is there a better/cleaner way to do it?

原文：https://stackoverflow.com/questions/30723758

更新时间：2023-09-01 22:09

最满意答案

 由于您的功能正在关闭flux ， SEM和depth因此您正在使用del s来修复返回的值，因此您遇到了问题。  
 flux是一个全局可变列表，每个通过你的函数你清除flux的内容，重新填充它，然后返回一个你之后存储为flux_n flux的引用。 这就是你在同一个底层list对象中的所有 flux_n点。 这同样适用于SEM_n 。  
 当您使用matplotlib绘图时，数据会被复制，因此一旦您创建了现有的图形，它们就不会受到影响。  
 试试：  
def data_reader(file_name, first_surface):
    flux = []
    SEM = []
    depth = []

    with open (file_name) as inf:
        lines = inf.readlines()
        for (i, line,) in enumerate(lines):
            if ' surface  %d' %first_surface in line:
                data = (lines[i+1].strip())
                fields = data.split()
                numbers = list(map(float,fields))  
                flux.append(numbers[0])
                SEM.append(numbers[1])
                first_surface += 1
                depth.append(first_surface - 101)                

    return (flux, SEM, first_surface)

You are having issues due to the fact that your function is closing over flux, SEM and depth so you are mucking up the returned values with the dels.  
flux is a global mutable list, each pass through your function your clear the contents of flux, re-fill it, and then return a reference to flux which you then store as flux_n. That is all of your flux_n point at the same underlying list object. The same applies for SEM_n. 
When you plot using matplotlib that data gets copied so your existing graphs are not affected once you make them. 
Try : 
def data_reader(file_name, first_surface):
    flux = []
    SEM = []
    depth = []

    with open (file_name) as inf:
        lines = inf.readlines()
        for (i, line,) in enumerate(lines):
            if ' surface  %d' %first_surface in line:
                data = (lines[i+1].strip())
                fields = data.split()
                numbers = list(map(float,fields))  
                flux.append(numbers[0])
                SEM.append(numbers[1])
                first_surface += 1
                depth.append(first_surface - 101)                

    return (flux, SEM, first_surface)

参考数据类成员访问者模式(reference data class member visitor pattern)

最满意答案

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