创建线程后调用execv(Calling execv after creating a thread)

 我对线程，进程，execv等都很新。我研究过并发现当你执行execv时，它会占用调用进程的空间。 我想知道当你在main中创建一个线程时会发生什么，然后直接在线程之后调用execv（不是在它完成之前，而是在创建线程之后）。 我知道execv将替换main但这是否意味着它也将替换线程或线程是否能够像正常一样执行和完成？ 
 
 我要问的一个小例子： 
 
  int main(){
      printf("hello from main!);
      char *buffer = "some data";

    if(pthread_creat(&mythreadpid, NULL, thread1, buffer){
        printf("ERROR!!");
     }

     execv(...) //do execv here

}

void *thread1(void *buffer){
  printf("calling from my thread!");

 //do something else

}
 
 我测试了这个并且我确实遇到了奇怪的行为，因为我的线程无法完成，因此我想知道这是否是它的原因 

I'm very new to threads, processes, execv, etc. I have researched and found that when you execute an execv, it takes the space of the calling process. I am wondering what happens when you create a thread in main, and then call execv, directly after the thread (not before it finishes but right after the thread is created). I know execv will replace main but does this mean that it will also replace the thread or will the thread be able to execute and complete like normal?
 
Small example of what I'm asking:
 
  int main(){
      printf("hello from main!);
      char *buffer = "some data";

    if(pthread_creat(&mythreadpid, NULL, thread1, buffer){
        printf("ERROR!!");
     }

     execv(...) //do execv here

}

void *thread1(void *buffer){
  printf("calling from my thread!");

 //do something else

}
 
I have tested this and I did experience strange behavior as my thread wouldn't complete so I want to know if this is the reason for it

原文：https://stackoverflow.com/questions/40296502