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为C ++构建Lua(Building Lua for C++)

根据Lua Wiki,如果将Lua 5.1或更高版本编译为C ++,它将使用C ++异常。 由于Lua是一个C库,它只引用makefile中的CC。 所以,我的想法是将CC重新定义为“g ++”,因此我不必修改makefile。

make generic CC="g++"

我能够毫无问题地构建Lua。 但是,现在当我将C ++应用程序链接到Lua(静态)库时,我收到许多Lua函数的未定义引用错误(lua_checklstring,lua_pushinteger等)。

当我使用gcc构建Lua时,我的应用程序链接成功。

make generic CC="gcc"

我是否错误地编译Lua for C ++? 我假设我需要以某种方式使用g ++,因为Lua源代码包含对cplusplus的预处理器检查以确定是否应该启用C ++异常。


According to the Lua Wiki, if Lua 5.1 or later is compiled as C++, it will use C++ exceptions. Since Lua is a C library it only references CC in the makefile. So, my idea was to redefine CC as "g++" so I don't have to modify the makefile.

make generic CC="g++"

I was able to build Lua without any problems. However, now when I link my C++ application to the Lua (static) library I receive undefined reference errors for many Lua functions (lua_checklstring, lua_pushinteger, etc).

When I build Lua using using gcc my application links successfully.

make generic CC="gcc"

Am I compiling Lua for C++ incorrectly? I assume I need to use g++ somehow since the Lua source code contains preprocessor checking for cplusplus to determine if C++ exceptions should be enabled.


原文:https://stackoverflow.com/questions/20839883
更新时间:2022-09-05 11:09

最满意答案

使用不可能的基于渐变的优化器。 您需要使用无梯度方法。 与OpenMDAO 2.2相比,没有任何内置的方法来实施这种离散化。 您需要在问题类周围使用外部循环才能使其工作。

这是一个简单的例子:

import numpy as np
from openmdao.api import Problem, ScipyOptimizeDriver, ExecComp, IndepVarComp

# build the model
prob = Problem()
indeps = prob.model.add_subsystem('indeps', IndepVarComp())
indeps.add_output('x', 3.0)
indeps.add_output('y', -4.0)

prob.model.add_subsystem('paraboloid', ExecComp('f = (x-3)**2 + x*y + (y+4)**2 - 3'))

prob.model.connect('indeps.x', 'paraboloid.x')
prob.model.connect('indeps.y', 'paraboloid.y')

# setup the optimization
prob.driver = ScipyOptimizeDriver()
prob.driver.options['optimizer'] = 'SLSQP'

prob.model.add_design_var('indeps.y', lower=-50, upper=50)
prob.model.add_objective('paraboloid.f')

prob.setup()


for x in np.arange(-10,12,2): 
    prob['indeps.x'] = x

    # could call just run_model if no optimization was desired
    #prob.run_model()

    # for each value of x, optimize for y
    prob.run_driver()

    # minimum value
    print(prob['paraboloid.f'])

    # location of the minimum
    print(prob['indeps.x'])
    print(prob['indeps.y'])

Using a gradient based optimizer that is not possible. You would need to use a gradient free method. As over OpenMDAO 2.2 there is not any built in way to enforce that kind of discretization. You would need to use an external loop around the problem class to get that to work.

Here is a simple example:

import numpy as np
from openmdao.api import Problem, ScipyOptimizeDriver, ExecComp, IndepVarComp

# build the model
prob = Problem()
indeps = prob.model.add_subsystem('indeps', IndepVarComp())
indeps.add_output('x', 3.0)
indeps.add_output('y', -4.0)

prob.model.add_subsystem('paraboloid', ExecComp('f = (x-3)**2 + x*y + (y+4)**2 - 3'))

prob.model.connect('indeps.x', 'paraboloid.x')
prob.model.connect('indeps.y', 'paraboloid.y')

# setup the optimization
prob.driver = ScipyOptimizeDriver()
prob.driver.options['optimizer'] = 'SLSQP'

prob.model.add_design_var('indeps.y', lower=-50, upper=50)
prob.model.add_objective('paraboloid.f')

prob.setup()


for x in np.arange(-10,12,2): 
    prob['indeps.x'] = x

    # could call just run_model if no optimization was desired
    #prob.run_model()

    # for each value of x, optimize for y
    prob.run_driver()

    # minimum value
    print(prob['paraboloid.f'])

    # location of the minimum
    print(prob['indeps.x'])
    print(prob['indeps.y'])

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