“和”和“或”的操作顺序是什么？(What is the order of operations for 'and' and 'or'?)

 在Python中是这样的： 
 
def blackjack_check(hand): # hand is a tuple
    winning_cards = [10,'Jack','Queen','King']
    if hand[0] in winning_cards and hand[1] == 'Ace':
        return True
    elif hand[0] == 'Ace' and hand[1] in winning_cards:
        return True
    else:
        return False
 
 与此相同...？ 
 
def blackjack_check(hand): # hand is a tuple
    winning_cards = [10,'Jack','Queen','King']
    if (hand[0] in winning_cards and hand[1]=='Ace' or 
        hand[0] == 'Ace' and hand[1] in winning_cards):
        return True
    else:
        return False
 
 我可以使用第二个代码块而不是第一个吗？ 它会消除额外的elif声明，而且看起来更清晰。 我关心的是'和'和'或'运营商是如何工作的。 这两个'和'比较是分开的，'或'比较它们吗？ 是否有'和'和'或'的操作顺序？ 我运行代码，它可以同时工作，但我想确保我完全理解操作员的工作方式。 

In Python is this:
 
def blackjack_check(hand): # hand is a tuple
    winning_cards = [10,'Jack','Queen','King']
    if hand[0] in winning_cards and hand[1] == 'Ace':
        return True
    elif hand[0] == 'Ace' and hand[1] in winning_cards:
        return True
    else:
        return False
 
the same as this...?
 
def blackjack_check(hand): # hand is a tuple
    winning_cards = [10,'Jack','Queen','King']
    if (hand[0] in winning_cards and hand[1]=='Ace' or 
        hand[0] == 'Ace' and hand[1] in winning_cards):
        return True
    else:
        return False
 
Can I use the second code block instead of the first? It would eliminate an extra elif statement and it just seems cleaner. My concern is how the 'and' and 'or' operators work. Are the two 'and' comparisons separate and the 'or' compares them? Is there an order of operations for 'and' and 'or'? I ran the code and it works both ways but I want to make sure I understand exactly how the operators work.

原文：https://stackoverflow.com/questions/38733885