首页 \ 问答 \ 在不知道其命名空间的情况下卸载JavaScript库(Unload JavaScript Libraries without knowing their namespace)

在不知道其命名空间的情况下卸载JavaScript库(Unload JavaScript Libraries without knowing their namespace)

我想知道是否有可能卸载JavaScript库(例如<script src="http://code.jquery.com/jquery-1.10.1.min.js"></script> )而不知道它命名空间。 我删除了元素,但jQuery仍然可用。 显然我可以把$和jQuery擦掉,但这不是我想要实现的。

这个问题不是关于jQuery,它可能是任意的JavaScript导入。

编辑:

为了解决我的问题,是否有可能解决函数原点,就像浏览器在其检查器中所做的那样? 类似函数是在导入X中的第360行定义的吗?

谢谢! 亚历山德罗


I'd like to know whether theres a possibility to unload JavaScript libraries (e.g. <script src="http://code.jquery.com/jquery-1.10.1.min.js"></script>) without knowing its namespace. I removed the element but jQuery is still available. Obviously I could just wipe $ and jQuery away but thats not what I'd like to achieve.

This question is not about jQuery, it could be any arbitrary JavaScript Import.

Edit:

To reverse my question is it possible to resolve a functions origin, like the browsers do in their Inspectors? Like function is defined at Line 360 in Import X?

Thank you! Alessandro


原文:https://stackoverflow.com/questions/20285770
更新时间:2023-09-18 06:09

最满意答案

默认情况下,Zend Framework期望URL中的参数采用/key/value的形式。 尝试这个:

http://mydomain.com/controller/action/key1/value1

print_r($request->getParams());

结果是:

Array
(
    [controller] => controller
    [action] => action
    [key1] => value1
)

编辑:正如其他人提到的,如果你想坚持使用http://mydomain.com/controller/action/value1你应该看看Zend_Controller_Router


For default, Zend Framework expects the parameters in URL to be in the form of /key/value. Try this:

http://mydomain.com/controller/action/key1/value1

print_r($request->getParams());

The result is:

Array
(
    [controller] => controller
    [action] => action
    [key1] => value1
)

Edit: as others mentioned, If you want to stick with http://mydomain.com/controller/action/value1 you should take a look at Zend_Controller_Router.

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