首页 \ 问答 \ 比较器的NoSuchMethodError?(NoSuchMethodError for comparator?)

比较器的NoSuchMethodError?(NoSuchMethodError for comparator?)

当我在android中运行我的程序时,我在这一行得到了以下异常。

private PriorityQueue<Creature> turnqueue = new PriorityQueue<Creature>(new TurnComparator());

FATAL EXCEPTION: GLThread 18092
Process: com.buckriderstudio.clonequest, PID: 10171
java.lang.NoSuchMethodError: No direct method <init>(Ljava/util/Comparator;)V in class Ljava/util/PriorityQueue; or its super classes (declaration of 'java.util.PriorityQueue' appears in /system/framework/core-libart.jar)

这是我的比较器的样子:

public class TurnComparator implements Comparator<Creature> {    
    @Override
    public int compare(Creature c1, Creature c2) {
        if (c1.getNextMove() < c2.getNextMove()) return -1;
        if (c1.getNextMove() > c2.getNextMove()) return 1;
        else return 0;
    }   
}

它似乎是某种兼容性问题,但我不知道如何解决这个问题。 Android根本不支持Comparator ,还是需要更改它才能解决这个问题? 什么是比较PriorityQueue的良好兼容替代品?


I get the below exception on this line when I run my program in android.

private PriorityQueue<Creature> turnqueue = new PriorityQueue<Creature>(new TurnComparator());

FATAL EXCEPTION: GLThread 18092
Process: com.buckriderstudio.clonequest, PID: 10171
java.lang.NoSuchMethodError: No direct method <init>(Ljava/util/Comparator;)V in class Ljava/util/PriorityQueue; or its super classes (declaration of 'java.util.PriorityQueue' appears in /system/framework/core-libart.jar)

This is how my comparator looks:

public class TurnComparator implements Comparator<Creature> {    
    @Override
    public int compare(Creature c1, Creature c2) {
        if (c1.getNextMove() < c2.getNextMove()) return -1;
        if (c1.getNextMove() > c2.getNextMove()) return 1;
        else return 0;
    }   
}

It seems it is some kind of compatibility issue but I'm not sure how to fix this. Does Android not support a Comparator at all or do I need to change it a bit to fix this? What would be a good compatible substitute for comparing a PriorityQueue?


原文:https://stackoverflow.com/questions/36103606
更新时间:2023-11-18 11:11

最满意答案

只需使用FileShare.None以独占方式打开它:

fs = new FileStream("bridge.ini", FileMode.Open, FileAccess.ReadWrite, FileShare.None);

作为一边......如果我是你,我会用这个部分using包装:

using (var fs = new FileStream("bridge.ini", FileMode.Open, FileAccess.ReadWrite, FileShare.None))
{
}

这样,流就被妥善处理了。 目前,我没有在代码中看到关闭流的任何地方(也许你在别的地方做它,因为你已经声明你的流不在这个方法中,但是是的)。


After idea of own Stream, I disassembly FileStream and discovered getter/setter Position.

Solution:

    string precteno = sr.ReadToEnd();
    precteno = stringModificator(precteno);
    fs.Position = 3;
    sw.Write(precteno);

相关问答

更多

相关文章

更多

最新问答

更多
  • 获取MVC 4使用的DisplayMode后缀(Get the DisplayMode Suffix being used by MVC 4)
  • 如何通过引用返回对象?(How is returning an object by reference possible?)
  • 矩阵如何存储在内存中?(How are matrices stored in memory?)
  • 每个请求的Java新会话?(Java New Session For Each Request?)
  • css:浮动div中重叠的标题h1(css: overlapping headlines h1 in floated divs)
  • 无论图像如何,Caffe预测同一类(Caffe predicts same class regardless of image)
  • xcode语法颜色编码解释?(xcode syntax color coding explained?)
  • 在Access 2010 Runtime中使用Office 2000校对工具(Use Office 2000 proofing tools in Access 2010 Runtime)
  • 从单独的Web主机将图像传输到服务器上(Getting images onto server from separate web host)
  • 从旧版本复制文件并保留它们(旧/新版本)(Copy a file from old revision and keep both of them (old / new revision))
  • 西安哪有PLC可控制编程的培训
  • 在Entity Framework中选择基类(Select base class in Entity Framework)
  • 在Android中出现错误“数据集和渲染器应该不为null,并且应该具有相同数量的系列”(Error “Dataset and renderer should be not null and should have the same number of series” in Android)
  • 电脑二级VF有什么用
  • Datamapper Ruby如何添加Hook方法(Datamapper Ruby How to add Hook Method)
  • 金华英语角.
  • 手机软件如何制作
  • 用于Android webview中图像保存的上下文菜单(Context Menu for Image Saving in an Android webview)
  • 注意:未定义的偏移量:PHP(Notice: Undefined offset: PHP)
  • 如何读R中的大数据集[复制](How to read large dataset in R [duplicate])
  • Unity 5 Heighmap与地形宽度/地形长度的分辨率关系?(Unity 5 Heighmap Resolution relationship to terrain width / terrain length?)
  • 如何通知PipedOutputStream线程写入最后一个字节的PipedInputStream线程?(How to notify PipedInputStream thread that PipedOutputStream thread has written last byte?)
  • python的访问器方法有哪些
  • DeviceNetworkInformation:哪个是哪个?(DeviceNetworkInformation: Which is which?)
  • 在Ruby中对组合进行排序(Sorting a combination in Ruby)
  • 网站开发的流程?
  • 使用Zend Framework 2中的JOIN sql检索数据(Retrieve data using JOIN sql in Zend Framework 2)
  • 条带格式类型格式模式编号无法正常工作(Stripes format type format pattern number not working properly)
  • 透明度错误IE11(Transparency bug IE11)
  • linux的基本操作命令。。。