如何捕获try-with-resource语句中close方法抛出的异常(How to catch exception thrown by close method in try-with-resource statement)

 同 
 
 br.form['q'] = sys.argv 
 
 您在此处分配字符串列表 而不是字符串。 
 
>>> type(sys.argv)
<type 'list'>
>>> type(sys.argv[0])
<type 'str'>
>>>
 
 您想要标识要通过索引分配的特定字符串。 
 
 鉴于你在帖子中的内容很可能是索引1（因为索引0是脚本的名称）。 也许吧 
 
 br.form['q'] = sys.argv[1] 
 
 会为你做的。 当然，它也可能是另一个索引，具体取决于您的特定应用/需求。 
 
 请注意@Dougal在下面的有用注释中观察到，函数中的函数参数word未被使用。 你正在调用你的dictionary函数发送它sys.argv然后应该引用函数内的word 。 该类型不会仅更改您在函数内引用命令行args的名称。 word的想法是好的，因为它避免使用全局变量。 如果你提到使用全局变量（不是真的鼓励），那么建议删除word ，因为它会让人感到困惑）。 
 
 所以你的陈述应该真正阅读 
 
 br.form['q'] = word[1] 

With 
 
br.form['q'] = sys.argv
 
you are assigning a list of strings here instead of a string.
 
>>> type(sys.argv)
<type 'list'>
>>> type(sys.argv[0])
<type 'str'>
>>>
 
You want to identify a specific string to assign via an index.
 
Most likely it will be be index 1 given what you have in your post (and since index 0 is the name of the script). So perhaps
 
br.form['q'] = sys.argv[1]
 
will do for you. Of course it could be another index too, depending on your particular application/needs.
 
Note as @Dougal observes in a helpful comment below, the function parameter word in the function is not being used. You are calling your dictionary function sending it sys.argv and then ought to refer to word inside the function. The type doesn't change only the name that you refer to the command line args inside your function. The idea of word is good as it avoids the use of global variables. If you refer to use globals (not really encouraged) then removing word is recommended as it will be confusing to have it there).
 
So your statement should really read
 
br.form['q'] = word[1]