base64引导到base64(base64 to guid to base64)

 我目前正在研究MongoDb作为一​​种可能的数据库选项，而且我在处理Guid序列化时遇到了麻烦。 起初我认为这可能是C＃驱动程序序列化中的一个错误，但现在我认为这更可能是我的天真假设。 
 
 为了帮助我将Bson base64表示法来回转换为Guids，我写了几个小小的PowerShell函数来帮助： 
 
function base64toguid  
{  
    param($str);  
    $b = [System.Convert]::FromBase64String($str);
    $hex = "";
    foreach ($x in $b) {
        $hex += $x.ToString("x2");
    }
    $g = new-object -TypeName System.Guid -ArgumentList $hex;
    return $g;
}


function guidtobase64
{
    param($str);
    $g = new-object -TypeName System.Guid -ArgumentList $str;
    $b64 = [System.Convert]::ToBase64String($g.ToByteArray());
    return $b64;
}
 
 我遇到的问题的一个示例： 
 
:) guidtobase64("53E32701-9863-DE11-BD66-0015178A5E3C");
ASfjU2OYEd69ZgAVF4pePA==
:) base64toguid("ASfjU2OYEd69ZgAVF4pePA==");

Guid
----
0127e353-6398-11de-bd66-0015178a5e3c
 
 从mongo外壳： 
 
:) mongo
MongoDB shell version: 1.6.5
connecting to: test
> b = new BinData(3, "ASfjU2OYEd69ZgAVF4pePA==");
BinData(3,"ASfjU2OYEd69ZgAVF4pePA==")
> b.hex();
127e353639811debd66015178a5e3c
>
 
 正如你所看到的，我找回的Guid与我放入的不匹配。我的函数和hex（）返回相同的东西。 如果您比较原始结果和结果： 
 
 53E32701-9863-DE11-BD66-0015178A5E3C 
 0127e353-6398-11de-bd66-0015178a5e3c 
 
 你可以看到前三组十六进制对被颠倒过来，但最后两组不是。 这让我觉得有一些关于Guid.ToString（），我不明白。 
 
 任何人都可以教育我吗？ 

I'm currently researching MongoDb as a possible database option, and I'm having trouble dealing with Guid serialization. I thought at first maybe this was a bug in the C# driver's serialization, but now I think it's more likely a naive assumption on my part.
 
To help me convert the Bson base64 representations back and forth to Guids, I wrote a couple of little powershell functions to help:
 
function base64toguid  
{  
    param($str);  
    $b = [System.Convert]::FromBase64String($str);
    $hex = "";
    foreach ($x in $b) {
        $hex += $x.ToString("x2");
    }
    $g = new-object -TypeName System.Guid -ArgumentList $hex;
    return $g;
}


function guidtobase64
{
    param($str);
    $g = new-object -TypeName System.Guid -ArgumentList $str;
    $b64 = [System.Convert]::ToBase64String($g.ToByteArray());
    return $b64;
}
 
An example of the issue I'm having:
 
:) guidtobase64("53E32701-9863-DE11-BD66-0015178A5E3C");
ASfjU2OYEd69ZgAVF4pePA==
:) base64toguid("ASfjU2OYEd69ZgAVF4pePA==");

Guid
----
0127e353-6398-11de-bd66-0015178a5e3c
 
And from the mongo shell:
 
:) mongo
MongoDB shell version: 1.6.5
connecting to: test
> b = new BinData(3, "ASfjU2OYEd69ZgAVF4pePA==");
BinData(3,"ASfjU2OYEd69ZgAVF4pePA==")
> b.hex();
127e353639811debd66015178a5e3c
>
 
So as you can see, the Guid I get back doesn't match what I put in. My function and hex() return the same thing. If you compare the original to the result:
 
53E32701-9863-DE11-BD66-0015178A5E3C
 0127e353-6398-11de-bd66-0015178a5e3c
 
You can see that the first 3 sets of hex pairs are reversed, but the last 2 sets are not. This makes me think there is something about Guid.ToString() that I don't understand.
 
Can anyone educate me please?

原文：https://stackoverflow.com/questions/5172134