awk命令：如何告诉它区分空格和制表符分隔符(awk command: how to tell it to distinguish between space and tab delimiter)

 我使用这个命令， awk '{print $1}' "$line" ，从一个看起来像这样的文件中获取一列数据:(下划线表示制表符作为分隔符，例如是三列数据） 
 
Joe Jonas_____8_____45  
Cersei Lann_____4_____23  
Bo Tox_____6_____28  
Mis Ter Yo_____7_____89  
 
 当我运行命令时，说要获取第一列，但输出显示如下： 
 
Joe  
Cersei  
Bo  
Mis  
 
 如何使命令忽略第一列数据中的空格？ 

I used this command, awk '{print $1}' "$line", to get a column of data from a file that looks like this:(underscores represent tab as a delimiter, example is a three-column data)
 
Joe Jonas_____8_____45  
Cersei Lann_____4_____23  
Bo Tox_____6_____28  
Mis Ter Yo_____7_____89  
 
When I run the command, say to get the first column, the output, however, showed it like this: 
 
Joe  
Cersei  
Bo  
Mis  
 
How can I make the command to ignore the spaces within the data of the first column?

原文：https://stackoverflow.com/questions/38473781