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案例类在Scala中映射(Case class to map in Scala)

有人知道如果有一个很好的方法,我可以转换一个Scala案例类实例,例如

case class MyClass(param1: String, param2: String)
val x = MyClass("hello", "world")

进入某种映射,例如

getCCParams(x) returns "param1" -> "hi", "param2" -> "3"

它适用于任何案例类,而不仅仅是预定义的类。 我发现你可以通过写一个询问底层Product类的方法来提取case类名,例如

def getCCName(caseobj: Product) = caseobj.productPrefix 
getCCName(x) returns "MyClass"

所以我正在寻找一个类似的解决方案,但对于case类的字段。 我想象一个解决方案可能需要使用Java反射,但是如果案例类的底层实现发生变化,我会讨厌在未来的Scala版本中写出一些可能会出现的错误。

目前,我正在使用Scala服务器,并使用案例类定义协议及其所有的消息和异常,因为它们是一个如此美丽,简洁的结构。 但是,我需要将它们转换成Java映射,以便通过消息传递层发送以供客户端实现使用。 我目前的实现只是为每个案例类定义一个翻译,但是找到一个通用的解决方案是很好的。


Is there a nice way I can convert a Scala case class instance, e.g.

case class MyClass(param1: String, param2: String)
val x = MyClass("hello", "world")

into a mapping of some kind, e.g.

getCCParams(x) returns "param1" -> "hello", "param2" -> "world"

Which works for any case class, not just predefined ones. I've found you can pull the case class name out by writing a method that interrogates the underlying Product class, e.g.

def getCCName(caseobj: Product) = caseobj.productPrefix 
getCCName(x) returns "MyClass"

So I'm looking for a similar solution but for the case class fields. I'd imagine a solution might have to use Java reflection, but I'd hate to write something that might break in a future release of Scala if the underlying implementation of case classes changes.

Currently I'm working on a Scala server and defining the protocol and all its messages and exceptions using case classes, as they are such a beautiful, concise construct for this. But I then need to translate them into a Java map to send over the messaging layer for any client implementation to use. My current implementation just defines a translation for each case class separately, but it would be nice to find a generalised solution.


原文:https://stackoverflow.com/questions/1226555
更新时间:2023-05-19 08:05

最满意答案

据我所知,如果cookbook_file存在,就不可能有利于测试。 但是如果没有找到该文件,您可以让厨师继续运行而不是失败。

cookbook_file "/etc/cron.d/#{service}" do
  source "etc/cron.d/#{service}"
  owner "root"
  group "root"
  mode "0644"
  ignore_failure true
end

As far as I know, it is not possible to test in advantage if the cookbook_file exists. But you can make chef continue the run instead of failing, if it didn't find the file.

cookbook_file "/etc/cron.d/#{service}" do
  source "etc/cron.d/#{service}"
  owner "root"
  group "root"
  mode "0644"
  ignore_failure true
end

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