首页 \ 问答 \ Android适配器是适配器设计模式的一个例子吗？(Are android adapters an example of Adapter Design pattern?)

Android适配器是适配器设计模式的一个例子吗？(Are android adapters an example of Adapter Design pattern?)

 Android适配器是否使用适配器设计模式？ GoF设计模式书将适配器设计模式描述为  
 
  适配器模式将类的接口转换为客户期望的另一个接口。 适配器允许类一起工作，否则由于不兼容的接口。  
 
 有一个目标接口，适配器实现并且客户端使用（期望），并且有一个适配器，适配器委托客户端发出的所有请求。  
 我知道它的理论和现实世界模式适配器接口看起来并不完全一样，但我仍然无法弄清楚android适配器适应什么（目标接口是什么）以及实际请求的适配器。  
 我检查了这个 ， 这个和这个 。 但是他们都没有解释清楚Android适配器是如何适配器设计模式的。 事实上， 第一和第二个答案有些矛盾。  
 有人可以解释一下吗？ 

Do Android adapters use Adapter Design pattern? The GoF design patterns book describes Adapter Design Pattern as  
 
 The Adapter Pattern converts the interface of a class into another interface the clients expect. Adapter lets classes work together that couldn’t otherwise because of incompatible interfaces. 
 
There's a target interface which the adapter implements and the client uses(expects) and there is an adaptee to which the adapter delegates all the requests made by client. 
I understand that its theory and real world pattern adapter interfaces don't exactly look like it, but still I can't figure out what the android adapters adapt(what target interface) and to which adaptee are the requests actually made to. 
I have checked this, this and this. But none of them explain clearly how is the android adapter the adapter design pattern. The 1st and 2nd answers, in fact, are somewhat conflicting.  
Can anyone please explain this?

原文：https://stackoverflow.com/questions/41626980

更新时间：2023-08-01 09:08

最满意答案

 Python字符串文字使用反斜杠作为转义字符。 字符串文字"\b"将包含退格字符（ASCII 0x8），就像"\n"将包含换行符一样。 它不会包含“反斜杠b”，正如你需要正则表达式工作一样。  
 要获得“反斜杠b”，您需要在字符串文字中转义反斜杠，或者分别使用原始字符串"\\b"或r"\b" 。  
regex = re.compile(old_name + r"\b", re.IGNORECASE)
 
 通常，原始字符串用于Python中的正则表达式，因此不需要每个反斜杠加倍。  
 阅读https://docs.python.org/3/reference/lexical_analysis.html#string-and-bytes-literals  
 
 注意： "\s"作用是因为 - 与"\b"或"\n"相反 - 它在Python字符串文字中没有特殊含义，所以它实际上成为正则表达式的“反斜杠s”。 

Python string literals use the backslash as an escape character. The string literal "\b" will contain the backspace character (ASCII 0x8), just like "\n" will contain a newline. It will not contain "backslash b", as you would need for the regex to work. 
To get "backslash b" you need to escape the backslash in the string literal, or use a raw string, which is "\\b" or r"\b", respectively. 
regex = re.compile(old_name + r"\b", re.IGNORECASE)
 
Commonly, raw strings are used for regex in Python, so you don't need to double every backslash. 
Read https://docs.python.org/3/reference/lexical_analysis.html#string-and-bytes-literals 
 
Side note: "\s" works because - in contrast to "\b" or "\n" - it means nothing special in a Python string literal, so it actually becomes "backslash s" for the regex.

Android适配器是适配器设计模式的一个例子吗？(Are android adapters an example of Adapter Design pattern?)

最满意答案

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