首页 \ 问答 \ AJAX调用[object%20Object]而不是URL(Symfony)(AJAX calls [object%20Object] instead of URL (Symfony))

AJAX调用[object%20Object]而不是URL(Symfony)(AJAX calls [object%20Object] instead of URL (Symfony))

在小枝我使用data-post-url="{{ path('ajax')}}"所以我可以通过使用var path = $("#edit-url-js").data();

然而,不要去http://localhost/happysaucer/web/app_dev.php/ajax它到http://localhost/happysaucer/web/app_dev.php/profile/ [object%20Object]

这是奇怪的,因为当我console.log(路径)'路径'变量它返回正确的网址。 当我对url进行硬编码时,'path'变量返回ajax调用。

AJAX电话:

$(document).ready(function(){

var path = $("#edit-url-js").data();

$(".option-js").on("change", function() {

    $.ajax({
        url: path,
        type: "post",
        data: "test",
        success: function(data) {

        }
    });

});
});

控制器操作

/**                                                                                   
* @Route("/ajax", name="ajax")
*/
public function ajaxAction(Request $request)    
{

    $r = new JsonResponse();

    return $r->setData([
        'success' => true,
    ]);
}

枝条代码

<div class="consumeable-container" id="edit-url-js" data-post-url="{{ path('ajax')}}">

In twig I use data-post-url="{{ path('ajax')}}" so I can get the url in javascript by using var path = $("#edit-url-js").data();

However instead of going to http://localhost/happysaucer/web/app_dev.php/ajax it goes to http://localhost/happysaucer/web/app_dev.php/profile/[object%20Object]

Which is weird because when I console.log(path) the 'path' variable it return the right url. When I hardcode the url the 'path' variable returns the ajax call works like it should.

AJAX call:

$(document).ready(function(){

var path = $("#edit-url-js").data();

$(".option-js").on("change", function() {

    $.ajax({
        url: path,
        type: "post",
        data: "test",
        success: function(data) {

        }
    });

});
});

Controller Action

/**                                                                                   
* @Route("/ajax", name="ajax")
*/
public function ajaxAction(Request $request)    
{

    $r = new JsonResponse();

    return $r->setData([
        'success' => true,
    ]);
}

Twig code

<div class="consumeable-container" id="edit-url-js" data-post-url="{{ path('ajax')}}">

原文:https://stackoverflow.com/questions/50003024
更新时间:2023-08-05 14:08

最满意答案

从base / default目录复制purchaseorder.phtml文件,然后将其粘贴到当前模板中。 现在您可以在当前目录中更改purchaseorder.phtml的内容,它不会影响基本文件。如下所示,

复制自

应用程序/设计/前端/基/默认/模板/支付/表格/ purchaseorder.phtml

粘贴到

应用程序/设计/前端/基/ current_theme /模板/支付/表格/ purchaseorder.phtml

覆盖部分时,文件夹结构应类似于默认模板文件夹结构,如current_theme / template / form / payment / purchaseorder.phtml 。 抱歉英语不好。


Copy purchaseorder.phtml file from base/default directory then paste it in your current template. Now you can alter content of it purchaseorder.phtml in your current directory, it wont affect the base file.Like below,

Copy from

app/design/frontend/base/default/template/payment/form/purchaseorder.phtml

Paste to

app/design/frontend/base/current_theme/template/payment/form/purchaseorder.phtml

When you override a section, the folder structure should resemble the default template folder structure like current_theme/template/form/ payment/purchaseorder.phtml . sorry for bad english.

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